Question 14 Туре: МCQUESTION 14Use these findings to answer the question.Compound X is optically inactive and has the formulaC 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. CompoundY absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is analdehyde with formula C 7H 60. The other fragment is glyoxal, (CHO) 2.The structure of Y is:PhPnType: MCQUESTION 15Use these findings to answer the question.Compound X is optically inactive and has the formulaC 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. CompoundY absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is analdehyde with formula C 7H 6O. The other fragment is glyoxal, (CHO) 2.The structure of Z is:

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Compound X is optically inactive and has the formulaC 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is an aldehyde with formula C 7H 6O. The other fragment is glyoxal, (CHO) 2. The structure of Y is: Ph Ph

Compound X is optically inactive and has the formulaC 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is an aldehyde with formula C 7H 6O. The other fragment is glyoxal, (CHO) 2. The structure of Y is: Ph Ph

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Compound X is optically inactive and has the formula C 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is an aldehyde with formula C 7H 6O. The other fragment is glyoxal, (CHO)2. Which of the following answers is correct? Select all that are correct.
Compound AA has a molecular formula of C3H6O and gives a positiveresult using Tollen’s reagent. The reaction of compound AA with hotacidified potassium permanganate, KMnO4 gives compound BB. Thecatalytic hydrogenation of compound AA with nickel, Ni producedcompound CC. The reaction of compound BB with ethanamine,CH3CH2NH2 produces compound DD I) Draw the structural formula of compounds AA, BB, CC and DD. 2)Name the type of chemical reaction for the formation of compound CC.
An optically active monoterpene (compound A) with molecular formula C10H18O undergoes catalytic hydrogenation to form an optically inactive compound with molecular formula C10H20O (compound B). When compound B is heated with acid, followed by reaction with O3 and then with dimethyl sulfide, one of the products obtained is 4-methylcyclohexanone. Give possible structures for compounds A and B.
Compound J, C16H16Br2, is optically active. On treatment with strong base, compounds K and L (each C16H14) are formed; K and L each absorb only 2 equivalents of hydrogen when reduced over a Pd/C catalyst. Compound K reacts with ozone to give phenylacetic acid (C6H5CH2COOH), while similar treatment of L gives 2 products. One product, M, is an aldehyde with formula C7H6O; the other product is glyoxal (CHO)2. Draw the structure of compound L.
Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr) which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (Ch3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which reacts with 2 equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and Pt catalyst to give 2-methylpropylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.
Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2 SO4 gives E (C10 H16), which decolorizes two equivalents of Br2 to give F (C10H16 Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to give isobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.
10. Compound X (C4H9Br) reacts by heating with NaOH in H2O to form Y. The compound Y then undergoes acid catalysed hydration by H2SO, in 180°C to form 2-methyl prop-1-ene. (e) Determine the structure of X and Y. (f) Predict a MAJOR product when compound Y reacts with H2SO4 in 140 C. (g) Draw a structural isomer of X. Name the isomer using IUPAC nomenclature. (h) Describe a chemical test to distinguish between compound Y and 1-butanol.
Туpе: MC QUESTION 14 Use these findings to answer the question. Compound X is optically inactive and has the formulaC 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is an aldehyde with formula C 7H 60. The other fragment is glyoxal, (CHO) 2. The structure of Y is: Ph Ph Ph Pn Туpe: MC QUESTION 15 Use these findings to answer the question. Compound X is optically inactive and has the formulaC 16H 16Br 2. On treatment with strong base, X gives hydrocarbon Y, C 16H 14. Compound Y absorbs 2 equivalents of hydrogen when reduced over a palladium catalyst and reacts with ozone to give two fragments. One fragment Z, is an aldehyde with formula C 7H 60. The other fragment is glyoxal, (CHO) 2.
Compound A (C11H23Br) is a secondary alkyl halide. On being heated with a solution of sodium ethoxide in ethanol, compound A yielded a mixture of two alkenes B and C, each having molecular formula C11H22. Catalytic hydrogenation of the major isomer B or the minor isomer C gave only 3,5-diethylheptane. Draw structures for compounds A, B, and C consistent with these observations.
An organic compound A of unknown structure was found to have a molecular formula C8H16. When A was poured in water and heated, compound B having a molecular formula C8H18O was formed. B upon heating with sulfuric acid was converted to C as the major product which is identical to A. Ozonolysis of C gave one molecule each of two different products D and E, both having a molecular formula C4H8O. Write the reactions involved and determine the structure of A,B,C,D and E.
2-bromo-2-methylbutane undergoes hydrolysis reaction with water, H2O toform compound W. Compound X and compound Y are produced when 2-bromo-2-methylbutane undergoes elimination reaction with alcoholic ofsodium hydroxide, NaOH. (i) Draw the structural formula of compounds W, X and Y
Compound A and compound B both have molecular formula C6H12. Both compounds produce epoxides when treated with a peroxy acid (RCO3H). The epoxide resulting from compound A was treated with aqueous acid (H3O+) and the resulting diol has no chiral centers. Identify the two possible structures for compound A (enter two numbers separated by commas with no spaces, e.g. "1,2") The epoxide resulting from compound B was treated with (H3O*) and the resulting diol was a meso compound. Identify compound B 2 3 potn 7 1 5 6 4 8