Compound A has molecular formula C7H7X. Its ¹H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C-NMR shows five signals. The mass spectrum of A shows a peak at m/z = 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The ¹H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The ¹H-NMR spectrum of C shows four signals - a triplet at 1.24 ppm, a singlet at 2.32 ppm, a quartet at 4.14 ppm, and a singlet at 7.42 ppm. The 13C-NMR spectrum of C shows seven signals. - Identify compound C, explaining your reasoning

Compound A has molecular formula C7H7X. Its ¹H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C-NMR shows five signals. The mass spectrum of A shows a peak at m/z = 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The ¹H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The ¹H-NMR spectrum of C shows four signals - a triplet at 1.24 ppm, a singlet at 2.32 ppm, a quartet at 4.14 ppm, and a singlet at 7.42 ppm. The 13C-NMR spectrum of C shows seven signals. - Identify compound C, explaining your reasoning

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter17: Alcohols And Phenols

Section17.SE: Something Extra

Problem 55AP: A compound of unknown structure gave the following spectroscopic data: Mass spectrum: M+=88.1 IR:...

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A compound of unknown structure gave the following spectroscopic data: Mass spectrum: M+=88.1 IR: 3600 cm-1 1Î—NMR: 1.4 Î´ (2 H, quartet, J=7 Hz); 1.2 Î´ (6H, singlet): 1.0 Î´ (1 H, singlet); 0.9 Î´ (3 H, triplet, J=7 Hz) 13CNMR: 74, 35, 27, 25 Î´ (a) Assuming that the compound contains C and H but may or may not contain O, give three possible molecular formulas (b) How many protons (H) does the compound contain? (c) What functional groups(s) does the compound contain? (d) How many carbons does the compound contain? (e) What is the molecular formula of the compound? (f) What is the structure of the compound? (g) Assign peaks in the moleculeâ€™s 1HNMR spectrum corresponding to specific protons.
When measured on a spectrometer operating at 200 MHz, chloroform (CHCl3) shows a single sharp absorption at 7.3 Î´. (a) How many parts per million downfield from TMS does chloroform absorb? (b) How many hertz downfield from TMS would chloroform absorb if the measurement were carried out on a spectrometer operating at 360 MHz? (c) What would be the position of the chloroform absorption in Î´ units when measured on a 360 MHz spectrometer?
Compound A, a hydrocarbon with M+=96 in its mass spectrum, has the 13C spectral data given below. On reaction with BH3, followed by treatment with basic H2O2. A is converted into B, whose, 13C spectral data are also given below. Propose structures for A and B. Compound A Broadband-decoupled l3C NMR: 26.8, 28.7, 35.7, 106.9, 149.7 DEPT-90: no peaks DEPT-135: no positive peaks; negative peaks at 26.8, 28.7, 35.7, 106.9 Compound B Broadband-decoupled 13C NMR: 26.1, 26.9, 29.9, 40.5, 68.2 DEPT-90: 40.5 DEPT-135: positive peak at 40.5 ; negative peaks at 26.1, 26.9. 29.9, 68.2
Compound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C-NMR shows five signals. The mass spectrum of A shows a peak at m/z = 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The 1H-NMR spectrum of C shows…
Compound A has molecular formula C7H7X. Its ¹H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C- NMR shows five signals. The mass spectrum of A shows a peak at m/z 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The ¹H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The ¹H-NMR spectrum of C shows…
Compound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.25 ppm and two doublets, one at 7.28 ppm and one at 7.39 ppm. The singlet has an integral of three and the doublets each have an integral of two. The mass spectrum of A shows a peak at m/z = 126 and another peak at m/z = 128; the relative height of the two peaks is 3:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning
Compound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.
The 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.
A compound contains only C, H and O. The mass spectrum shows peaks at m/z = 58 and 43. What is the structure of the compound?
What is the structure of a compound of molecular formula C1H1402 that shows a strong IR absorption at 3150-2850 cm1 and gives the following 'H NMR absorptions: 1.4 (triplet, 6 H), 4.0 (quartet, 4 H), and 6.8 (singlet, 4 H) ppm?
What is the structure of the compound with the formula C10H14O, which shows a strong broad signal near 3300 cm-1, the 1H-NMR spectrum is: 1.44 ppm (9H singlet) 4.97 ppm (2H doublet) 7.32 ppm (2H doublet)
An unknown compound has the molecular formula C7H14O, and its 1H NMR and 13C NMR spectra are shown below. Determine the structure of the unknown compound and draw it below. Note that there are no peaks above 3 ppm in the 1H NMR, and the numbers present on the 1H NMR are the integration values for each set of peaks.