Completely determine the resultant of the forces shown in the figure. Option: R= 957lb down to the right at 32.2°, (0, 1.38) (2.19,0) R= 759lb down to the right at 32.2°, (0, 1.38) (2.19,0) R= 957lb down to the left at 32.2°, (0, 1.38) (2.19,0) R= 759lb down to the left at 32.2°, (0, 1.38) (2.19,0)

The two forces, F1 = 20 kN and F2 = 4 %3D kN are acting on a system shown in the figure. If 01 = 45° and 02 = 45°, what will be the values of Rx, Ry, R %3D %3D and the angle (0) makes by R with .the positive x-axis Y+ 02 F2 Y- Ry (1) R,= F; (2) R,= Fy; (3)R = (R + R;); (4)0 = tan1 Rx اخترأحد الخيارات a. Rx = 20.13 kN, Ry = 4.99 kN, R = 20.74 kN and 0 = 13.92° %3D b. Rx = 17.72 kN, Ry = 9.31 kN, R = 20.02 kN and 0 = 27.72° c. Rx = 20.95 kN, Ry = 5.62 kN, R = 21.70 kN and 0 = 15.02° %3D d. Rx = 16.97 kN, Ry = 11.31 kN, R = 20.39 kN ande = 33.68°