Complete the truth table of the following sequential circuit JQ D Q B K Q' Q' Next State 1 1 1 x0000--- 10011001 Y A A B 0 1 0 1 0 1 0 1 1 1

Problem_#07] Use a Karnaugh Map to derive the simplified SOP expression for the truth table shown below. Inputs Output ABCD X 0000 0 0001 1 0010 1 0011 0 0100 0101 0110 0111 1000 1001 1010 101 1 1100 1101 1110 11 11 0 0 1 1 1 0 1 0 1 1 0 1

Hardware & Architecture HW #5 - 100 Pts (15 Pts - 5 Pts Each) Given the following truth table 3. Inputs Output A B C 0 0 0 0 0 0 1 0 0 1 0 1 0 1 1 I 1 0 0 0 1 0 1 0 110 1 1 1 I 0 a. Find the UN-SIMPLIFIED SOP Boolean Expression for the Output. b. Find the UN-SIMPLIFIED POS Boolean Expression for the Output. c. Simplify the SOP Expression using Boolean algebra. 4. (15 Pts - 5 Pts Each) Given the following truth table Inputs a. Find the UN-SIMPLIFIED SOP Boolean Expression for the Output. Output X Y Z 0 0 0 0 0 0 1 1 0 1 0 1 0 I 1 0 1 0 0 1 b. Find the UN-SIMPLIFIED POS Boolean Expression for the Output. 1 0 1 1 1 1 0 0 1 1 1 0 c. Simplify the POS Expression using Boolean algebra.

Problem_#06] Using the truth table below, develop a simplified SOP expression using a Karnaugh Map. Inputs Output ABC X 1 000 001 010 011 100 101 110 1 0 1

Problem_#06] Derive the SOP and POS expression for the truth table shown below. ABC X 000 0 001 1 010 0 011 0 100 1 101 1 110 0 111 1

Find the maxterm expansion of the truth table and create a digital circuit that works with it.

AB 00 01 11 10 The logic expression corresponding to the above Karnaugh map is (the blank cell is a 0) OC +A' + B' O C+A' + B' OC +A' OC +A+B O None of the above

Q2: Use a Karnaugh map to simplify the following standard SOP expression: XYZ + XYZ + XYZ + XYZ + XYZ + XYZ 101 010 100

Consider the circuit shown below: Y. X Cik- J Q J-K flip-flop K Q The characteristic equation of the new flip-flop created from the above circuit is a. Qn(Y+X')+X'YQ'n b. QnY'+X')+XYQ c. Y'(X'+Qn)+XY'Q'n d. X'(Y+Qn)+XY'Q'n