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Complete the design of the amplitier shown so that IDS =1.23mA and Av = Vo/Vi 1. Rs1 = 54.987 • x ohm 2. Rs2 = 251.324 • x ohm +20V 8KO C2 Volt) I Dss = 2mA V, = -2V 1KO vilt) 100KO Rs1 Rs2

Complete the design of the amplitier shown so that IDS =1.23mA and Av = Vo/Vi 1. Rs1 = 54.987 • x ohm 2. Rs2 = 251.324 • x ohm +20V 8KO C2 Volt) I Dss = 2mA V, = -2V 1KO vilt) 100KO Rs1 Rs2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Complete the design of the amplifier shown so that IDS =1.23mA and Av = Vo/Vi = -1 1. Rsl = 54.987 • x ohm 2. Rs2 = 251.324 + x ohm +20V , 8ΚΩ C2 Vo(t) I Dss = 2mA 1KO Vp = -2V vilt) 100KΩ Rs1 Rs2 C3
Transcribed Image Text:Complete the design of the amplifier shown so that IDS =1.23mA and Av = Vo/Vi = -1 1. Rsl = 54.987 • x ohm 2. Rs2 = 251.324 + x ohm +20V , 8ΚΩ C2 Vo(t) I Dss = 2mA 1KO Vp = -2V vilt) 100KΩ Rs1 Rs2 C3
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