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Compare your results to those given below:
ln(N!) = NhnN-N
(1)
N In(N!) Calculated | In(N!)(1)
20
42.3
39.9
50
148.5
145.6
100
363.7
360.5
Check all that apply.
The value calculated using Stirling's approximation provides a slight overestimation of the
actual value.
The value calculated using Stirling's approximation equals the actual value.
The value calculated using approximation (1) provides a slight overestimation of the
actual value.
The value calculated using approximation (1) provides a slight underestimation of the
actual value.
The value calculated using Stirling's approximation provides a slight underestimation of
the actual value.
The value calculated using approximation (1) equals the actual value.
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Transcribed Image Text:Compare your results to those given below: ln(N!) = NhnN-N (1) N In(N!) Calculated | In(N!)(1) 20 42.3 39.9 50 148.5 145.6 100 363.7 360.5 Check all that apply. The value calculated using Stirling's approximation provides a slight overestimation of the actual value. The value calculated using Stirling's approximation equals the actual value. The value calculated using approximation (1) provides a slight overestimation of the actual value. The value calculated using approximation (1) provides a slight underestimation of the actual value. The value calculated using Stirling's approximation provides a slight underestimation of the actual value. The value calculated using approximation (1) equals the actual value. Submit Request Answer
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