Compare your results to those given below: ln(N!) = NhnN-N (1) N In(N!) Calculated | In(N!)(1) 20 42.3 39.9 50 148.5 145.6 100 363.7 360.5 Check all that apply. The value calculated using Stirling's approximation provides a slight overestimation of the actual value. The value calculated using Stirling's approximation equals the actual value. The value calculated using approximation (1) provides a slight overestimation of the actual value. The value calculated using approximation (1) provides a slight underestimation of the actual value. The value calculated using Stirling's approximation provides a slight underestimation of the actual value. The value calculated using approximation (1) equals the actual value. Submit Request Answer

Compare your results to those given below: ln(N!) = NhnN-N (1) N In(N!) Calculated | In(N!)(1) 20 42.3 39.9 50 148.5 145.6 100 363.7 360.5 Check all that apply. The value calculated using Stirling's approximation provides a slight overestimation of the actual value. The value calculated using Stirling's approximation equals the actual value. The value calculated using approximation (1) provides a slight overestimation of the actual value. The value calculated using approximation (1) provides a slight underestimation of the actual value. The value calculated using Stirling's approximation provides a slight underestimation of the actual value. The value calculated using approximation (1) equals the actual value. Submit Request Answer