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- Example F =100 kD two forces Fi=l00 EP, z =200LN is epplied at point A which have the coordinates (3,3). Reduce the system of fores shown in the Ague to an equinalent force -coaue system at pont o. 3י וו, ו> E 11;EV I 2 T3- 3D For.. T3 3D - Force Syste Q8 The 180-lb force is applied at point A of the bracket. Determine the moments of this force about point B, about point C, and about the line BC. Ans. Mc= -2840k Ib.in MBc =2540 Ib.in 6" 13" 180 lb 145 09 15" 12 IIam of Mechanics/Firs X E Monthly Exam of Mechanics/Firs x PQLS ZSh4aZJdw9EBqROOfLVx M7KUGF6 9bgBbd-YGOXA/formResponse * For the force shown in figure, find the resultant (R) by component method F=10 kN 0=30° R=5 kN R=10 KN O R=15 kN O R=60 KN For the forces shown in figure, find just (EFx) components F=4 kN F=2 kN 0-30 A=300
- with the following modifications: Add an additional force P = 20kN acting downwards at point BThe triangular block below is subjected to the Loads P=1200 lb and 400 lb. If AB=8 in, and BC is 6in., resolve each load into components normal and tangential to AC.Determine the intensity and position of the resultant R lf two forces F1 and F3 and torque M that acts on the metal profile given as in the figure,if: F1= 2kN a=2,10m F2= 5kN b=2,10m M=24kNm c=3,10m
- M. = M-400x 0.15cos30-320 x 0.3= 0 M = 148 Nm CCW mm N 00 Example : Replace the three forces acting on the bent beam by a single equivalent force R. Specify the distance x from the point O in which the line of action of R passes. N 007 160 N 250 mm 250 mm 250 mm 125 mm 240 NA member is loaded with the given system of forces as shown in figure. Find the moment about A & B. Where AB = AD = 80 m, F1=35 N F2=5N, F3=39N, F4=32N, theta1=35degree , theta2= 50degree, theta3=55degree & theta4=30degree. The Moment about "A" (in Nm) = The Moment about "B" (in Nm) = The Moment about "C" (in Nm) = The Moment about "D" (in Nm) = Short AnswerThree force are a s teel Plaste a c ting on with 4m Leng th by um width Shown in figure The se three forces are required to caure a hovizontal re sultanta cting through Point if F= yOS N 1. The Ualue of hori outal resaltant Ris 2 The value of force Pis Q3: The value of force Ti
- НОМE WORK 3 Determine the resultant force at A. for the figure below Hint : 1- Find the position of all points A,B.C (x, y., z) 2. Find Fas und FAC 3. Find Tanl and Iracl 4. Find FAg = F UA and Fac = F UAC 5- Finally find R and a, B.y 3m Fc= 500N FB= 500N 3m 5m 3m B 2m 4m 5mFor the force shown in figure, find the * resultant (R) by component method F=4 kN F=3 kN 0=60° 0=30°The steel box wrench (E=29,000ksi, v=0.32) is loaded with a 40-lb horizontal force and a 25-lb vertical force. Find the following for an element located at point B on Section a-a: 24 in. 1. The non-vanishing resultant internal moments on section a-a are which of the following? 4 in. a. (160 i- 600 j+960 k)in · Ib b. (-160 i+600 j+960 k ) in · lb c. (-960 i+160 j+600 k)in - lb d. (-960 i -160 ј-600 k)in-lb a e. none of the above 2. The normal and shear force components on section a-a are: a. V, = 65lb;V, = 40lb; N¸ = 25lb b. V, = 0;V, =40lb; N, = 25lb c. V, = 64;V, = 25lb; N, = 40lb d. V, =0;V, =-40lb; N¸ = -25lb e. none of the above 3. The non-vanishing stress components at point B are: 0̟ =1.60; t =-4.89ksi; а. 0, =-4.89; 7 =3.60ksi; 0, = 2.50ksi; T, d. o, = 4.91ksi; t =-4.89ksi; b. с. =-4.89ksi; е. none of the above 4. The principal stresses at point B from most tensile to most compressive are: O1,02,0; =4.16,–0.8,–5.76 b. o,,0,,0, =5.76,0,–4.16 а. O1,02,0; =1.9,-2.45,-6.8 с. d.…