Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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**Unit 2: Problem-Solving with Distance and Time**

**Problem Statement:**
Cole biked at 5 mph for \(1 \frac{1}{2}\) hours. Which of the following choices show how far he biked?

- A) 5.5 miles
- B) 6.5 miles
- C) 7.5 miles
- D) 10 miles

**Explanation:**
To determine how far Cole biked, we need to use the formula for distance, which is:

\[ \text{Distance} = \text{Speed} \times \text{Time} \]

Here, the speed is 5 mph, and the time is \(1 \frac{1}{2}\) hours, which can be converted to 1.5 hours. Now, we multiply the speed by the time:

\[ \text{Distance} = 5 \, \text{mph} \times 1.5 \, \text{hours} = 7.5 \, \text{miles} \]

Therefore, the correct answer is:

C) 7.5 miles
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Transcribed Image Text:**Unit 2: Problem-Solving with Distance and Time** **Problem Statement:** Cole biked at 5 mph for \(1 \frac{1}{2}\) hours. Which of the following choices show how far he biked? - A) 5.5 miles - B) 6.5 miles - C) 7.5 miles - D) 10 miles **Explanation:** To determine how far Cole biked, we need to use the formula for distance, which is: \[ \text{Distance} = \text{Speed} \times \text{Time} \] Here, the speed is 5 mph, and the time is \(1 \frac{1}{2}\) hours, which can be converted to 1.5 hours. Now, we multiply the speed by the time: \[ \text{Distance} = 5 \, \text{mph} \times 1.5 \, \text{hours} = 7.5 \, \text{miles} \] Therefore, the correct answer is: C) 7.5 miles
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