CNNBC recently reported that the mean annual cost of auto insurance is 1020 dollars. Assume the standard deviation is 260 dollars. You take a simple random sample of 63 auto insurance policies. Find the probability that a single randomly selected value is less than 977 dollars. P(X < 977) = Find the probability that a sample of size n = 63 is randomly selected with a mean less than 977 dollars. P(M < 977) = Enter your answers as numbers accurate to 4 decimal places

Q: What is the probability that a first grade classroom of 20 students who are chosen randomly from the…

A: Given Information: Mean μ=100 Standard deviation σ=15 Sample size n=20

Q: The amount of time students study for a test is normally distributed with a mean of 3 hours and a…

A: Mean=μ=3Standard.deviation=σ=1.8Samplesize=n=30

Q: The SAT math scores of a particular high school in New Jersey are approximately normally…

A: From the empirical rule we know that 95% of the observations falls in (µ-2σ,µ+2σ)  Where µ is the…

Q: Suppose the mean percentage in Algebra 2B is 70% and the standard deviation is 8%. What percentage…

A: GivenMean(μ)=70%standard deviation(σ)=8%

Q: The mean marathon finishing time for men and women was 268 minutes and 280 minutes respectively.…

A: From the given information, The mean marathon finishing time for men and women was 268 minutes and…

Q: The mean IQ of 500 data science students is 151  and the standard deviation is 15. Assuming that the…

A:

Q: According to the Department of Education, 60% of college students enjoy taking Statistics. Suppose…

A: Let  X be the number of students who enjoy taking Statistics in a sample of 200. Given n = 200…

Q: A researcher measures the amount of food consumed by each dog in her lab. She finds that the mean…

A: It is given that mean amount of food is 12 oz and number of dogs is 16. The sum of squared…

Q: Tiger Woods hits an average driver 287.2 yards with a standard deviation of 24.6 yards. What is the…

A: The probability value is calculate by means of standard normal variate with the random variable,…

Q: Consider two investment options: Stock A and Stock B. Every $100 invested in Stock A yields a return…

A: The standard deviation for the portfolio is a function of the standard deviations of the assets that…

Q: cognitive psychologist has recently developed a test to measure the emotional intelligence of…

A: Given,mean(μ)=95standard deviation(σ)=10

Q: The mean of a test is 400 and the standard deviation is 75. It is normally distributed. A sample of…

A: 1] Mean μ=400 2] standard deviation σ=75 3] n=25 4] μx¯=400σx¯=σn=7525=15

Q: The average IQ of the adult population is 100. A researcher believes that average IQ of the…

A: The sample mean is calculated as follows: Mean = (69+79+89+99+109)/5           = 445/5           =…

Q: Suppose the mean percentage in Algebra 2B is 70% and the standard deviation is 8%. What percentage…

A:

Q: Average ACT = 540 with a standard deviation of 134. What is the probability that a high school…

A: X~N( μ , ?)μ=540     , ?=134Z-score =( x - μ )/?

Q: mar is trying out to be a firefighter.  On the written exam, the mean of everyone who takes the test…

A: given data, μ=54.5σ=3.1Omar scores exactly 0.75 standard deviations above the mean z=0.75raw score…

Q: An ABC new report stated that the mean distance that commuters in the United States travel each way…

A: Given : μ = 16 , σ= 8 and n= 75

Q: IQ scores for students at a prestigious university are normally distributed with a mean of 110 and a…

A:

Q: It is possible to have a standard deviation of -1 for some data set? True or False

A: See the below solution

Q: A candy manufacturer has replaced 5.17% of their chocolate bars with a new mystery flavor. Find the…

A: Given: Sample size (n) = 424 p(chocolate bars with a new mystery flavor) = 5.17% = 0.0517

Q: Determine the probability of seeing a Z score of -5.28 or one with a larger absolute value.

A: Z = -5.28 P( Z &gt; -5.28) = 1 – P(Z &lt; -5.28) = 1 – 0 = 1 P(Z &lt; -5.28) = 0 (From Excel…

Q: In 2000, the average height of a woman aged 20–74 years was 64 inches with an increase of…

A:

Q: The highway mileages of 147 cars are in a file named CARS2.+ These cars are 2003 models. Find the…

A: Mean Formula The mean formula is defined as the sum of the observations divided by the total number…

Q: at is the probability that you could randomly

A: mean = 112.5 standard deviation = 16.4 What is the probability that you could randomly select a…

Q: Please show the full solution and proper notation and terminology. A small town contains 1,500…

A:

Q: ow that a random individual will fall between 107 and 103 .if the mean IQ is 100 the standard…

A: Consider a random variable X which represents IQ of the individual.    X follows normal distribution…

Q: A student will spend 15 hours average each week in class. If the standard deviation is 2 hours, what…

A: Given that mean=15 and standard deviation = 2 Let, X= number of hours spent by a student in the…

Q: Suppose that replacement times for washing machines are normally distributed with a mean of 8.8…

A:

Q: The distances golf balls travel under laboratory testing conditions are normally distributed. The…

A:

Q: A researcher claims that the stomachs of blue crabs from Location A contain more fish than the…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013…

A: given  mean μ=2.24 standard deviation σ=1.2 n=80

Q: Listed below are the amounts of net worth (in millions of dollars) of the ten wealthiest celebrities…

A:

Q: What is the standard error of the mean?

A: Standard error: Standard error is a measure which explains how accurate are the sample means to…

Q: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the…

A: Mean()=129000standard deviation()=30000

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.