CNNBC recently reported that the mean annual cost of auto insurance is 1000 dollars. Assume the standard deviation is 112 dollars. You will use a simple random sample of 94 auto insurance policies. You may assume original population is approximatley normally distributed, and round your answers to three decimals. Find the probability that a single randomly selected policy has a mean value between 972.3 and 1017.3 dollars. P(972.3

Q: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the…

A: From the provided information,Mean (µ) = 162000Standard deviation (σ) = 36000Sample size (n) = 58

Q: large study of the heights of 360 adult men found that the mean height was 69 inches tall. The…

A: According to the given information in this question We need to find the following probability

Q: CNNBC recently reported that the mean annual cost of auto insurance is 1010 dollars. Assume the…

A: Given,mean(μ)=1010standard deviation(σ)=266sample size(n)=78

Q: he distribution of heights of adult males has a mean of 69 inches and a standard deviation of 4…

A: Solution-: Let, X= The distribution of heights of adult males Given: (inches) We find, P[ he…

Q: A recent poll found that 59% of adults believe the state of moral values is poor. For 400 randomly…

A: Here, n = 400 and p = 0.59

Q: Working in the garden pulling weeds/planting flowers burns an average of 200 calories per hour. If…

A: given data μ=200σ=9normal distribution P(200<x<225)=?

Q: Tiger Woods hits an average driver 287.2 yards with a standard deviation of 24.6 yards. What is the…

A: The probability value is calculate by means of standard normal variate with the random variable,…

Q: .. Lori just bought a set of 4 tires for her car. The life of a tire is normally distributed with a…

A:

Q: The sample of five companies in the aerospace industry was surveyed as to their return on investment…

A: We have to find sample variance s2  and sample standard deviation...

Q: An electrical firm manufactures light bulbs that have a length of life that is normally distributed…

A: According to the given information, we have Mean = 819 hours Standard deviation = 45 hours

Q: The mean height of male college students in a large city is 68 inches and the standard deviation is…

A: Solution

Q: Furnace repair bills are normally distributed with a mean of 263 dollars and a standard deviation of…

A: Here, µ = 263 and σ = 25.

Q: A leading magazine (like Barron's) reported at one time that the average number of weeks an…

A: Since, you have asked multiple question, we will solve the first question for you. If you want any…

Q: If the mean exam score of a class was 75%, with a standard deviation of 15%,what percent of students…

A: Given,mean(μ)=0.75standard deviation(σ)=0.15

Q: Convert score 46 to z-score if the mean is 40 and the standard deviation is 4.

A: The definition of a z-score is:   z = (X - μ) / σ

Q: A study conducted by the Center for Population Economics at the University of Chicago studied the…

A:

Q: William revealed that he makes 1,000,000 dollars annually. The average annual income in the country…

A:

Q: The average number of pounds of red meat a person consumes each year is 196 with a standard…

A: We are given,μ = 196σ = 22n = 60

Q: The average time a person spends shopping in a grocery store is 43 minutes.  If the time is normally…

A: Given:  The average time a person spends shopping in a grocery store is 43 minutes.  The time is…

Q: A college is composed of (0.25) men and (0.75) women. It is known that (0.60) of men and (0.20) of…

A:

Q: The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

A: GivenMean(μ)=6.04standard deviation(σ)=0.21Sample size(n)=33

Q: Adult Golden Retrievers have a mean weight of 64 pounds with a standard deviation of 8 pounds. If…

A: In this scenario, it is known that the  mean weight is 64 pounds with a corresponding standard…

Q: The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

A:

Q: he manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that…

A:

Q: Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the…

A:

Q: Find the probability that a single randomly selected salary that doesn't exceed 181000 dollars.…

A: The random variable X is defined as the salary for graduates which follows normal distribution with…

Q: The weights of ice cream cartons are normally distributed with a mean weight of 11 ounces and a…

A: Given : μ=11 ounceσ=0.6 ounceX~N(μ=11,σ2=0.62)Let, for sample of size n,x¯~Nμx¯=μ,σx¯2=σn2

Q: TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013…

A: given  mean μ=2.24 standard deviation σ=1.2 n=80

Q: A large study of the heights of 550 adult men found that the mean height was 71 inches tall. The…

A: Given data  Normal distribution μ = 71σ = 7N = 550 empirical rule : approximately  68 -95- 99.7 %…

Q: Scores on the SAT test have a mean of 1518 and a standard deviation of 325. If 100 students are…

A: Scores on the SAT test have a mean of 1518 and a standard deviation of 325.

Q: find the probability that the mean time of a sample of 15 Americans who shower will be less than 12…

A:

Q: In a bell-shaped distribution, 95 % of the data falls within 1 standard deviation of the mean.

A: Given that In a bell-shaped distribution, 95 % of the data falls within 1 standard deviation of the…

Q: The average number of minutes per week that teenagers spend texting is 250.0. Assume the standard…

A: Normal distribution is a continuous distribution which has many real life applications. Normal curve…

Q: Assume that people playing World of Warcraft in a week has a normal distribution with a mean of 54…

A: The probability that a randomly selected person played more than 89 hours is obtained below, From…

Q: A researcher measures the amount of sugar in several cans of the same soda. The mean is 39.01 with a…

A:

Q: Imagine a scenario where 100 people complete a self-esteem measure. Assume the standard deviation of…

A: