MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Question

Classify the lengths into 7 equally wide class.
Draw a histogram of the classified results


Actual lower limit Actual upper limit Frequency Relative frequency Cumulative frequency
Lengths
122
135
113
122
123
121
124
123
117
139
129
132
127
115
134
125
127
122
121
135
119
120
121
113
124
119
129
140
125
139
136
142
135
115
125
141
119
115
127
113
120
112
122
135
132
131
138
116
135
132
135
115
137
114
123
114
117
128
131
126
119
112
125
113
127
130
140
114
139
125
130
124
131
116
123
125
142
118
141
138
116
137
123
136
134
136
137
118
117
137
124
117
133
119
134
131
135
129
139
134
138
140
112
139
136
112
132
127
140
132
135
126
138
134
125
112
120
135
130
136
118
136
119
127
115
127
135
123
134
118
117
134
142
137
133
119
136
116
137
117
113
114
113
122
129
129
120
120
136
124
125
135
127
126
126
135
125
124
122
130
117
118
129
114
140
129
121
141
132
119
131
141
138
139
141
113
135
122
121
112
119
141
128
123
128
138
140
125
122
123
131
138
139
113
128
115
135
133
139
119
113
128
115
139
138
133
138
125
118
119
119
138
119
134
132
130
133
112
120
119
116
129
128
140
130
137
114
134
141
130
142
139
119
141
121
133
120
138
127
113
121
116
123
131
118
133
124
123
122
114
133
135
127
132
121
134
134
115
114
128
126
128
131
116
141
121
122
125
140
126
115
122
122
121
117
140
129
121
125
130
124
115
124
124
132
131
142
136
128
116
122
114
123
142
122
133
116
123
130
135
126
123
121
134
127
132
140
122
123
112
126
112
132
114
113
137
142
123
140
127

 

Use exce cells and show calculations.

Expert Solution
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Follow-up Questions
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Follow-up Question

Can you please show the cells how got frequency, relative frequency and cumulative frequency

4
Start with the minimum value as the lowest limit of the first class. Add 4 to it to obtain the upper
limit of the first class i.e., 116. Start with the next value 117 as the lower limit of the second class,
add 4 to obtain the upper limit. Repeat the same for the remaining classes.
The frequency distribution of the data is:
Actu Actu
al al
lowe uppe
r
r
limit limit
112 116 111.5
116.5 49
117 121 116.5 121.5 49
122 126 121.5 126.5 61
127 131 126.5 131.5 48
132 136 131.5 136.5 57
137 141 136.5 141.5 49
142 146 141.5
146.5 7
Total 320
Lower Upper
class class Freque Relative
bound bound ncy
frequency
ary
ary
49
320
49
320
61
320
48
320
57
320
49
320
7
320
1
= 0. 153125
= 0.153125
0.190625
=
= 0.15
= 0.178125
=
= 0.153125
= 0.021875
expand button
Transcribed Image Text:4 Start with the minimum value as the lowest limit of the first class. Add 4 to it to obtain the upper limit of the first class i.e., 116. Start with the next value 117 as the lower limit of the second class, add 4 to obtain the upper limit. Repeat the same for the remaining classes. The frequency distribution of the data is: Actu Actu al al lowe uppe r r limit limit 112 116 111.5 116.5 49 117 121 116.5 121.5 49 122 126 121.5 126.5 61 127 131 126.5 131.5 48 132 136 131.5 136.5 57 137 141 136.5 141.5 49 142 146 141.5 146.5 7 Total 320 Lower Upper class class Freque Relative bound bound ncy frequency ary ary 49 320 49 320 61 320 48 320 57 320 49 320 7 320 1 = 0. 153125 = 0.153125 0.190625 = = 0.15 = 0.178125 = = 0.153125 = 0.021875
Solution
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by Bartleby Expert
SEE SOLUTION
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

Can you please show the cells how got frequency, relative frequency and cumulative frequency

4
Start with the minimum value as the lowest limit of the first class. Add 4 to it to obtain the upper
limit of the first class i.e., 116. Start with the next value 117 as the lower limit of the second class,
add 4 to obtain the upper limit. Repeat the same for the remaining classes.
The frequency distribution of the data is:
Actu Actu
al al
lowe uppe
r
r
limit limit
112 116 111.5
116.5 49
117 121 116.5 121.5 49
122 126 121.5 126.5 61
127 131 126.5 131.5 48
132 136 131.5 136.5 57
137 141 136.5 141.5 49
142 146 141.5
146.5 7
Total 320
Lower Upper
class class Freque Relative
bound bound ncy
frequency
ary
ary
49
320
49
320
61
320
48
320
57
320
49
320
7
320
1
= 0. 153125
= 0.153125
0.190625
=
= 0.15
= 0.178125
=
= 0.153125
= 0.021875
expand button
Transcribed Image Text:4 Start with the minimum value as the lowest limit of the first class. Add 4 to it to obtain the upper limit of the first class i.e., 116. Start with the next value 117 as the lower limit of the second class, add 4 to obtain the upper limit. Repeat the same for the remaining classes. The frequency distribution of the data is: Actu Actu al al lowe uppe r r limit limit 112 116 111.5 116.5 49 117 121 116.5 121.5 49 122 126 121.5 126.5 61 127 131 126.5 131.5 48 132 136 131.5 136.5 57 137 141 136.5 141.5 49 142 146 141.5 146.5 7 Total 320 Lower Upper class class Freque Relative bound bound ncy frequency ary ary 49 320 49 320 61 320 48 320 57 320 49 320 7 320 1 = 0. 153125 = 0.153125 0.190625 = = 0.15 = 0.178125 = = 0.153125 = 0.021875
Solution
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by Bartleby Expert
SEE SOLUTION
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