The following values for sand are given: D10= 0.28 mm „D = 0.45 mm ,D300.7mm.60=Determine C (Coefficient of uniformity) and C (Coefficient of curvature) and state if it is a well graded or a poorly graded soil

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Answered: The following values for sand are…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Write each criterion that is satisfied for each classification. For the given data of soil A and B, DETERMINE THE FF AND SHOW COMPLETE SOLUTION. 1. Classify soil A using AASHTO method. 2. Classify soil B using USCS method. SIZE (MM) A B 4.75 100 100 2.36 97 100 2.00 92 98 0.850 87 92 0.425 59 88 0.180 42 79 0.150 26 70.1 0.075 20 61 No. 40 Fraction Characteristics LL 32 46 PL 20 24
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8. The grain size analysis for a soil is given as: asso a. Plot a grain-size distribution curve. b. Determine D10, D30, and D60 from the grain-size distribution curve. c. Calculate the uniformity coefficient, Co. d. Calculate the coefficient of curvature, Co Sieve No. 4 10 20 40 60 100 200 Pan Mass of soil retained (g) 28 42 48 128 221 86 40 24 Cu= Duo / Dio (c = (P30)² 2²/D₁x Duo
A sieve analysis of a soil sample of weight (400 g) was performed and the results were as follows. Required 1-Find the% passing and plot the gradient gradient. 2-Find the regularity coefficient and the Cu gradient
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3. The following are the results of a field unit weight determination test performed on the soil by means of the sand cone method. Calibrated dry density of Ottawa sand = 1570 kg/m³ Calibrated mass of Ottawa sand to fill the cone = 0.545 kg Mass of jar + cone + sand (before use) = 7.59 kg Mass of jar + cone + sand (after use) = 4.78 kg Mass of moist soil dug from hole = 3.007 kg Water content of moist soil = 10.2% Max dry unit weight = 19 kN/m³ a. Determine the moist unit weight of compacted soil in kN/m³. b. Find the dry unit weight in kN/m³. c. Compute the relative compaction in the field.
Q2- Classify the soil of following properties according to Unified and Textural Classification Systems; L.L= 40% P.L = 35% (show all calculations and steps). Size, mm 0.212 0.15 0.075 0.02 0.006 0.004 0.001 % finer 100 89 (50+N) 47 38 30 (5+N) N=5
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
Answer 4.8
Q1: A. Answer in True or False 1. A soil has a Cu =1, then it is considered as a poorly graded soll. 2. A soil has L.L-60% and P.L-35%, then it plots a point below the A-line in the plasticity car 3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 50% 4. Decreasing water content below shrinkage limit is accompanied with a decreasing in void ra 5. Water molecules are considered polar and known as dipoles. 6. Dry Density is the smallest density. 7. Capillary rise is directly proportional to the pore channel diameter. 8. The unconfined compressive strength is twice the undrained cohesion. 9. Piping or boiling occurs when effective stress equals to zero. 10. It is assumed that the secondary compression begins when the primary conso
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The following values for sand are given: D 10 = 0.28 mm „D = 0.45 mm ,D 30 0.7mm. 60= Determine C (Coefficient of uniformity) and C (Coefficient of curvature) and state if it is a well graded or a poorly graded soil