CI on Variance Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company's product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years. Construct a 95% confidence interval for o? and decide if the company’s claim that o² = 1 is valid. Assume the population of battery lives to be approximately normally distributed. a. 0.34 < o2 < 4.59. Because 95% confidence interval for o? is (0.34, 4.59), and the s2 is in that interval, we can conclude that the company's claim is valid = 0.815 O b. 0.29 < o² < 6.74. Because 95% confidence interval for o² is (0.29, 6.74), and 1 is in that interval, we can conclude that the company's claim that ơ² = 1 is valid O c. 0.29 < o² < 6.74. 95% confidence interval for o² is (0.29, 6.74) O d. 0.539 < o< 2.596. Because 95% confidence interval for o is (0.539, 2.596), and 1 is in that interval, we can conclude that the company's claim that ơ = 1 is valid
CI on Variance Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company's product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years. Construct a 95% confidence interval for o? and decide if the company’s claim that o² = 1 is valid. Assume the population of battery lives to be approximately normally distributed. a. 0.34 < o2 < 4.59. Because 95% confidence interval for o? is (0.34, 4.59), and the s2 is in that interval, we can conclude that the company's claim is valid = 0.815 O b. 0.29 < o² < 6.74. Because 95% confidence interval for o² is (0.29, 6.74), and 1 is in that interval, we can conclude that the company's claim that ơ² = 1 is valid O c. 0.29 < o² < 6.74. 95% confidence interval for o² is (0.29, 6.74) O d. 0.539 < o< 2.596. Because 95% confidence interval for o is (0.539, 2.596), and 1 is in that interval, we can conclude that the company's claim that ơ = 1 is valid
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
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Transcribed Image Text:CI on Variance
Defective alternator and corroded or loose battery charges are a few of the main causes of battery
degradation. A company producing automobile batteries is developing a prototype on their next product
and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample
of 5 prototype batteries were taken and in the course of the company's product development, have
measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years.
Construct a 95% confidence interval for o? and decide if the company's claim that o? = 1 is valid. Assume
the population of battery lives to be approximately normally distributed.
a. 0.34 < o2 < 4.59. Because 95% confidence interval for o² is (0.34, 4.59), and the s² = 0.815
is in that interval, we can conclude that the company's claim is valid
Ob.
0.29 < o2 < 6.74. Because 95% confidence interval for o? is (0.29, 6.74), and 1 is in that
interval, we can conclude that the company's claim that o2 = 1 is valid
O c. 0.29 < o² < 6.74. 95% confidence interval for o² is (0.29, 6.74)
O d. 0.539 < o< 2.596. Because 95% confidence interval for o is (0.539, 2.596), and 1 is in that
interval, we can conclude that the company's claim that o = 1 is valid
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