Question in photo Chromosome from an A1 cow:3'5'Microsatellite 412A100Beta casein A13'5'AThe same locus, but from an A2 cow's chromosome:3'5'Microsatellite 412A150Beta casein A23'5'a. You have a cow that produces A1 milk and has the following genotype: 412A100 BCA1/ 412A100the A2 cow's genotype is: 412A150 BCA2/cow that produces A2BCA1. This412A150 BCA2.mates withi.What is the genotype of the F1?ii.If you copy the microsatellite from the two parent cows and the F1 cow, what bandingpattern (DNA fragments) will you see from each sample? Draw the DNA fragments on thegel below, remembering that smaller (shorter) DNA fragments are found towards thebottom of the gel compared to longer DNA fragments.F1 (A1A1parentA2 parentphenotype)topbottom 4. Examine the figure below showing the location of a microsatellite (called 412A) and the beta caseingene on chromosome 3, from cows. There are two alleles of the microsatellite that exist in thepopulation: 412A100 and 412A150, The 100 and 150 represent the number of repeat units in themicrosatellite. There are two alleles of the beta casein gene: BCA1 and BCA2. The two BCA allelesdiffer by a single nucleotide in the coding region. The difference results in a change in the proteinsuch that the beta casein protein from BCA2 is more easily broken-down during digestion, makingthe milk more digestible than milk containing BCA1 proteins, for some people.In the figure below we see a predicted chromosomal map indicating the microsatellite and beta caseingenes. The arrows show the region of DNA that will be copied to assess the microsatellite genotypes.The bolded "A" and "C" below the beta casein gene shows the nucleotide that differs between the twoalleles.

First of all DNA is broken down with the help of certain specific restriction endonucleases into DNA fragments and then it is allowed to run through a gel matrix. The negatively charged DNA move towards the positively charged anode according to their molecular weight. The heavier DNA fragments will stay up and the lighter DNA fragments will move down during gel electrophoresis.Genotypes- A1- 412 A100 BCA1/412 A100 BCA1 A2- 412A150 BCA2/A2- 412A150 BCA2 F1- 412 A100 BCA1/A2- 412A150 BCA2 F1 obtained is intermediate of A1 and A2 parents. Hence the banding pattern obtained from a F1 would be intermediate between the two parents.