Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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LEARNING TASK 3
Choose from the following reasons below to prove the theorem. Some of them can
be used twice.
Factoring
Addition property of equality
Given
The arc of the whole circle is 360°
Inscribed angle theorem
Definition of supplementary angles
Substitution (steps 5 and 5)
Algebraic process (step 6)
Theorem: "If a quadrilateral in inscribed in a circle, then its opposite angles are
supplementary."
Given: Quadrilateral ABCD is inscribed in OE.
Prove: ZADC and ZABC are supplementary
ZDAB and ZDCB are supplementary
STATEMENT
1. Quadrilateral ABCD is inscribed in OE.
REASON
(1)
(2)
2. MLADC = =MABC
1
MADC
MLABC
M2DAB = ,ml
=-MDCB
1
MLDCB =MDAB
2.
Addition property of
equality
3. MLADC + MLABC
MĀBC +
-MĀDC
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Transcribed Image Text:LEARNING TASK 3 Choose from the following reasons below to prove the theorem. Some of them can be used twice. Factoring Addition property of equality Given The arc of the whole circle is 360° Inscribed angle theorem Definition of supplementary angles Substitution (steps 5 and 5) Algebraic process (step 6) Theorem: "If a quadrilateral in inscribed in a circle, then its opposite angles are supplementary." Given: Quadrilateral ABCD is inscribed in OE. Prove: ZADC and ZABC are supplementary ZDAB and ZDCB are supplementary STATEMENT 1. Quadrilateral ABCD is inscribed in OE. REASON (1) (2) 2. MLADC = =MABC 1 MADC MLABC M2DAB = ,ml =-MDCB 1 MLDCB =MDAB 2. Addition property of equality 3. MLADC + MLABC MĀBC + -MĀDC
(3)
4. MLADC + MLABC =(MABC +
MĀDC)
5. MABC + MADC = 360
6. MLADC + MLABC =(360)
7. MLADC + MLABC = 180
8. LADC and LABC are supplementary
9. MLDAB + MLDCB =MDCB +
(4)
Substitution (steps 4 and 5)
Algebraic process (step 6)
(5)
(6)
MDAB
10. MLDAB + M2DCB =(MDCB +
MDAB)
11. MDCB + .DAB = 360
Factoring
%3D
(7)
(8)
12. MLDAB + MLDCB =(360)
13. MLDAB + M2DCB = 180
(9)
(10)
%3D
14. ZDAB and ZDCB are supplementary
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Transcribed Image Text:(3) 4. MLADC + MLABC =(MABC + MĀDC) 5. MABC + MADC = 360 6. MLADC + MLABC =(360) 7. MLADC + MLABC = 180 8. LADC and LABC are supplementary 9. MLDAB + MLDCB =MDCB + (4) Substitution (steps 4 and 5) Algebraic process (step 6) (5) (6) MDAB 10. MLDAB + M2DCB =(MDCB + MDAB) 11. MDCB + .DAB = 360 Factoring %3D (7) (8) 12. MLDAB + MLDCB =(360) 13. MLDAB + M2DCB = 180 (9) (10) %3D 14. ZDAB and ZDCB are supplementary
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