Chemistry Question

Reaction at equilibrium is represented as:

$2H_{2\left(g\right) } + C{O}_{\left(g\right) }\iff C{H}_{3}O{H}_{\left(g\right)}$

Value of equilibrium constant (K_c) is given by:

$K_c = \frac{Product of concentration of products raised to the stoichiometric powers}{Product of concentration of reac\tan ts raised to stoichiometric powers}$

$K_c = \frac{\left[C{H}_{3}OH\right]}{{\left[H_2\right]}^2 \left[CO\right]}$ = 35 (at a fixed temperature)

The value of equilibrium constant is fixed at a particular temperature and is independent of the concentration of the  reactants or products.

Number of moles of H₂  = $5.27\times {10}^{-2} moles$

Number of moles of CH₃OH = 4.15 $\times {10}^{-3}$ moles

Volume of solution = 7.53 L