Chemistry Question

Given:

Weight of SO₃ is 61.5 g.

Weight of H₂O is 11.2 g.

Weight of H₂SO₄ is 56.6 g.

The given reaction is shown below.

$S{O}_3\left(g\right)+H_{2}O\left(l\right)\to H_{2}S{O}_4\left(aq\right)$

The molar mass of SO₃ is 80 g/mol.

The molar mass of H₂O is 18 g/mol.

The molar mass of H₂SO₄ is 98 g/mol.

Therefore, the number of moles of SO₃ is,

$\begin{array}{rcl}Moles& =& \frac{Weight}{Molarity}\\ & =& \frac{61.5 g}{80 g/mol}\\ & =& 0.76 mol\end{array}$

The number of moles of H₂O is,

$\begin{array}{rcl}Moles& =& \frac{Weight}{Molarity}\\ & =& \frac{11.2 g}{18 g/mol}\\ & =& 0.62 mol\end{array}$