The rate constant for this first-order reaction is 0.450 s⁻¹ at 400 °C. A → products How long, in seconds, would it take for the concentration of A to decrease from 0.800 M to 0.250 M? \[ t = \] There is a blank space provided for input. ### Explanation: The problem requires using the first-order reaction integrated rate law to calculate the time it takes for the concentration of reactant A to decrease from 0.800 M to 0.250 M. For a first-order reaction, the integrated rate law is given by: \[ t = \frac{1}{k} \ln \left(\frac{[A]_0}{[A]}\right) \] where: - \( t \) is the time, - \( k \) is the rate constant, - \([A]_0\) is the initial concentration, - \([A]\) is the concentration at time \( t \). In this problem: - \( k = 0.450 \, \text{s}^{-1} \), - \([A]_0 = 0.800 \, \text{M} \), - \([A] = 0.250 \, \text{M} \). The box labeled "TOOLS x10⁷" may be a utility for calculations or converting numbers to scientific notation.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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The rate constant for this first-order reaction is 0.450 s⁻¹ at 400 °C.

A → products

How long, in seconds, would it take for the concentration of A to decrease from 0.800 M to 0.250 M?

\[ t = \]

There is a blank space provided for input.

### Explanation:

The problem requires using the first-order reaction integrated rate law to calculate the time it takes for the concentration of reactant A to decrease from 0.800 M to 0.250 M. For a first-order reaction, the integrated rate law is given by:

\[ t = \frac{1}{k} \ln \left(\frac{[A]_0}{[A]}\right) \]

where:
- \( t \) is the time,
- \( k \) is the rate constant,
- \([A]_0\) is the initial concentration,
- \([A]\) is the concentration at time \( t \).

In this problem:
- \( k = 0.450 \, \text{s}^{-1} \),
- \([A]_0 = 0.800 \, \text{M} \),
- \([A] = 0.250 \, \text{M} \).

The box labeled "TOOLS x10⁷" may be a utility for calculations or converting numbers to scientific notation.
Transcribed Image Text:The rate constant for this first-order reaction is 0.450 s⁻¹ at 400 °C. A → products How long, in seconds, would it take for the concentration of A to decrease from 0.800 M to 0.250 M? \[ t = \] There is a blank space provided for input. ### Explanation: The problem requires using the first-order reaction integrated rate law to calculate the time it takes for the concentration of reactant A to decrease from 0.800 M to 0.250 M. For a first-order reaction, the integrated rate law is given by: \[ t = \frac{1}{k} \ln \left(\frac{[A]_0}{[A]}\right) \] where: - \( t \) is the time, - \( k \) is the rate constant, - \([A]_0\) is the initial concentration, - \([A]\) is the concentration at time \( t \). In this problem: - \( k = 0.450 \, \text{s}^{-1} \), - \([A]_0 = 0.800 \, \text{M} \), - \([A] = 0.250 \, \text{M} \). The box labeled "TOOLS x10⁷" may be a utility for calculations or converting numbers to scientific notation.
Expert Solution
Step 1

Initial concentration = 0.800 M 

Final concentration = 0.250 M 

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