
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Question

Transcribed Image Text:**Osmotic Pressure and Molar Concentration Calculation**
When 3.49 g of a nonelectrolyte solute is dissolved in water to make 755 mL of solution at 27 °C, the solution exerts an osmotic pressure of 879 torr.
**Questions:**
1. **What is the molar concentration of the solution?**
- **Concentration:** ___________ M
2. **How many moles of solute are in the solution?**
- **Moles of solute:** ___________ mol
3. **What is the molar mass of the solute?**
- **Molar mass:** ___________ g/mol
**Instructions:**
- Use the ideal gas law equation for osmotic pressure: \(\Pi = iMRT\), where:
- \(\Pi\) = osmotic pressure (in atms, convert torr to atm)
- \(i\) = van't Hoff factor (for nonelectrolytes, \(i = 1\))
- \(M\) = molarity (moles/L)
- \(R\) = ideal gas constant (\(0.0821 \, \text{L atm/mol K}\))
- \(T\) = temperature in Kelvin
- Convert the temperature from Celsius to Kelvin.
- Calculate the molar concentration from the given osmotic pressure.
- Calculate the number of moles of solute using the molarity and volume.
- Determine the molar mass using the mass of the solute and the number of moles calculated.
Expert Solution

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Step 1
Given :-
Mass of non-electrolyte solute = 3.48 g
Volume of solution = 755 mL
Temperature = 27°C
Osmotic pressure = 879 torr
To be calculated :-
- Molar concentration of solution
- Number of moles of solute
- Molar mass of solute
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