Mass of Zn 2.44 g Mass of Cu 0.063 g The mass of Zn and the mass of Cu in a coin are given in the table. How is the number of moles of Zn in the coin determined? A By multiplying 0.063 g by 65.38 g/mol By multiplying 2.44 g by 65.38 g/mol By dividing 2.44 g by 65.38 g/mol By dividing 65.38 g mol by 2.44g

Mass of Zn 2.44 g Mass of Cu 0.063 g The mass of Zn and the mass of Cu in a coin are given in the table. How is the number of moles of Zn in the coin determined? A By multiplying 0.063 g by 65.38 g/mol By multiplying 2.44 g by 65.38 g/mol By dividing 2.44 g by 65.38 g/mol By dividing 65.38 g mol by 2.44g

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Calculate the number of atoms in 12.45 grams of iron . 1.342 x 1023atoms 1.342 x 1022toms 0.223 atoms O 1.342 x 1024 atoms
4. Dichloroethane, a compound that is often used for dry cleaning, contains carbon, hydrogen, and chlorine. It has a molar mass of 99.0 g/mol. Analysis of a sample shows that it contains 24.3% carbon and 4.1% hydrogen and rest is chlorine. What is its molecular formula? 5. Calculate the number of oxygen atoms procent in 755.0 mg of nitrogendioxide gas.
Determine the mass in milligrams of 0.857 mol NH, CI. mg NH,Cl mass: Determine the mass in milligrams of 40.0 mmol H,SO̟. mg H,SO4 mass:
Suppose you have a sample of sodium weighing 12.40 g. How many atoms of sodium are present in the sample? What mass of potassium would you need to have the same number of potassium atoms as there are sodium atoms in the sample of sodium? atoms of sodium g of potassium
CHEMWORK With the advent of techniques such as scanning tunneling microscopy, it is now possible to "write" with individual atoms by manipulating and arranging atoms on an atomic surface. a. If an image is prepared by manipulating iron atoms and their total mass is 1.30 x 10-20 g, what number of iron atoms were used? 1 mole = 6.022 x 1023 atoms Fe atoms b. If the image is prepared on a platinum surface that is exactly 22 platinum atoms high and 13 platinum atoms wide, wha is the mass (grams) of the atomic surface? g Pt c. If the atomic surface were changed to ruthenium atoms and the same surface mass as determined in part b is used, what number of ruthenium atoms is needed to construct the surface? Ru atoms
How many moles of ammonia contain 1.51 x 1024 NH3 molecules? A) 2.51 mol B) 0.399 mol C) 0.251 mol D) 3.99 mol E) 25.1 mol How many molecules of methane gas, CH4, have a mass equal to 3.20 g? A) 1.20 x 1023 molecules B) 1.20 x 1024 molecules C) 1.93 x 1024 molecules D) 3.01 x 1023 molecules E) 3.01 x 1024 molecules
a. A 9.475 gram sample of copper is heated in the presence of excess chlorine. A metal chloride is formed with a mass of 20.05 g. Determine the empirical formula of the metal chloride. b. A 23.11 gram sample of manganese is heated in the presence of excess bromine. A metal bromide is formed with a mass of 90.32 g. Determine the empirical formula of the metal bromide.
Calculate the mass (in grams) of 4.59x1024 atoms of Cu. Calculate the number of atoms of Cu in 52.1 g of Cu. g atoms
a. How many ATOMS of boron are present in 5.24 grams of boron trifluoride? atoms of boron. b. How many GRAMS of fluorine are present in 3.30 x 1021 molecules of boron trifluoride grams of fluorine.
Which of these are correct/ true? A. 1 mole of He has the same amount of atoms than 1 mole of CaB. Avogadro’s number is the number of particles it takes to make 1 mole, whichis 6.022 x 1023 particlesC. The molar mass of NaCl is the same as the molar mass of ClD. The molar mass of Ar (arsenic) is 74.922 g/mo
What is the mass of oxygen atoms in 0.305 moles of Fe(CO)5 ?A. 17.0 gB. 59.7 gC. 24.4 gD. 4.88 g
Name each compound, and then calculate its mass. Express this value in scientific notation.