C,HBrO2, The strong peak at 1750 cm The molecular formula of an unknown compound is The proton NMR data is, 1.2d(6H, d), 4.2d(1H, t), 2.2d(2H, quintet), 4.93d(1H, septet), 1.08d(3H, t). What is the name of the unknown compound? ethyl 2-bromo-3-methylbutanoate 1-bromopropyl isobutyrate 1-bromoethyl 3-methylbutanoate Isopropyl 2-bromobutanoate
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- The molecular formula of an unknown compound is C7H13BrO2, The strong peak at 1750 cm^-1 The proton NMR data is, 1.2d(6H, d), 4.2d(1H, t), 2.2d(2H, quintet), 4.93d(1H, septet),1.08d(3H,t).What is the name of the unknown compound? Isopropyl 2-bromobutanoate 1-bromopropyl isobutyrate ethyl 2-bromo-3-methylbutanoate 1-bromoethyl 3-methylbutanoateProvide a structure for the compound C 5 H10 O. IN the 1H NMR, the peak at 1.05 is a doublet that integrates for 6H, the peak at 1.98 is a singlet tht integrates for 3H and the peak at 2.56 is a septet that integrates for 1H.Below are the ¹H NMR spectrum of triphenylmethanol, benzophenone, and bromobenzene. Identify the compound corresponding to each ¹H NMR spectrum and draw the structure next to the ¹H NMR spectrum. Assign ALL peaks in each of the three ¹H NMR spectra. Hint: Conjugated systems (benzophenone) including an electronegative atom will cause a more downfield shift of ring protons in ¹H NMR compared with non-conjugated systems (bromobenzene). 8 8 8 7 7 7 6 6 6 5 5 5 4 PPM 4 PPM 4 PPM 3 3 3 2 2 2 1 1 1 0 0 0
- I have an NMR spectrum. There are 5 peaks. There is a doublet at 9.6 ppm (integrates to 2H) where aldehydes usually arise, don't know why there is a doublet. There is another doublet at 6.8 ppm, again integrating to 2H. There is a singlet at 4.5 ppm, integrating to 1H. There is a quartet at 3.4 ppm integrating to 2H, and lastly there is triplet at 1.2 ppm integrating to 3H. i recofnize the ethyl group but don't understand the peak at 9.6 unless it is not an aldehyde.The proton nmr is 2H doublet at about 3.4 1H nonet at 1.5 6H doublet at about 1.p10. The proton NMR of a compound has the following peaks. Which compound below best fits the data? A OCH₂CH₂Cl NO₂ B OH CH-CH3 CI broad singlet 55.17 (1H) doublet o 1.49 (3H) quartet & 5.00 (1H) doublet o 7.22 (2H) doublet o 7.38 (2H) C CH₂ CH2-OH CH₂ D CH₂-OH CI
- Propose a structural formula for a compound of molecular formula C11 H1 402 by the given spectra, and explain your determination. LOD TRANSMETTRNCEIN 10 4000 כהל 1H 3100 3000 2H 2H 2000 220 200 180 160 HAVENUMBERI 6 1690 1500 PPM 140 120 100 PPM 80 1000 60 IR ¹H-NMR 2H 2H 199 3H 13C-NMR 2H 20 500(3) These natural compounds will have different numbers of 1H-NMR signals in different NMR solvents like CDC13 and methanol-d4. How many signals do you anticipate for each compound respectively in CDC13 and methanol-d4? LOCH 3 OHC. vanillin OH LOH acetoaminophen HO thymol5. Dibromomethane contains 2 equivalent protons, so just one signal on the H NMR spectrum for dibramomethane is expected to be seen. determine the expected chemical shift for the dibromomethane signal.
- answer the following questions about the 1-Butanol-,3-methyl-acetate H NMR 1- identify the number of the chemical shift of peaks, signals, and integration of the NMR 2-Justify the identity of the compound using the NMR (how does this NMR represent 1-Butanol-,3-methyl-acetate?)Interpret 1H and C13 NMR of Ethanol Include structure corresponding with peak please and thank youIdentify the significant absorption peaks by labeling them right on the spectrumand includethe spectrum in your laboratory report. Absorption peaks corresponding to the followinggroups should be identified: C—H (SP3) C—H (SP2) C—H (aldehyde) O—H C=O C=C (aromatic)aromatic substitution pattern C—OC—X (if applicable)