Charles's law states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas: (Figure 1) Figure V₁ K = 1/2 Lower temperature Smaller volume Higher temperature Larger volume 1 of 1 Part A A sample of gas in a balloon has an initial temperature of 2 °C and a volume of 1330 L. If the temperature changes to 80 °C, and there is no change of pressure or amount of gas, what is the new volume, V₂, of the gas? Express the volume numerically in liters. ▸ View Available Hint(s) V₂ = Submit Part B IVE ΑΣΦ T₂ = 3 [5] ΑΣΦ ? What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T₁=2 °C, V₁=1330 L) to a volume of 2660 L ? Assume no change in pressure or the amount of gas in the balloon. Express the temperature numerically in degrees Celsius. ► View Available Hint(s) L °C
Charles's law states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas: (Figure 1) Figure V₁ K = 1/2 Lower temperature Smaller volume Higher temperature Larger volume 1 of 1 Part A A sample of gas in a balloon has an initial temperature of 2 °C and a volume of 1330 L. If the temperature changes to 80 °C, and there is no change of pressure or amount of gas, what is the new volume, V₂, of the gas? Express the volume numerically in liters. ▸ View Available Hint(s) V₂ = Submit Part B IVE ΑΣΦ T₂ = 3 [5] ΑΣΦ ? What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T₁=2 °C, V₁=1330 L) to a volume of 2660 L ? Assume no change in pressure or the amount of gas in the balloon. Express the temperature numerically in degrees Celsius. ► View Available Hint(s) L °C
Transcribed Image Text:**MasteringChemistry: Chapter 8 Introduction to Gases - Attempt 1**
# Temperature and Volume
**Charles's Law** states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas. This can be represented mathematically as:
\[
\frac{V_1}{T_1} = \frac{V_2}{T_2}
\]
**Figure 1 Explanation:**
The figure depicts two images of a cylinder with pistons. In the image on the left, labeled "Lower temperature, Smaller volume," the gas molecules are closer together, indicating a smaller volume. There is a small flame underneath the cylinder. The right image, labeled "Higher temperature, Larger volume," shows the gas molecules more spread out after an increase in temperature, indicating a larger volume due to heating. The flame underneath is the same size as in the left image.
**Problem Statement:**
**Part A:**
A sample of gas in a balloon has an initial temperature of \(2 \, ^\circ\text{C}\) and a volume of \(1330 \, \text{L}\). If the temperature changes to \(80 \, ^\circ\text{C}\), with no change in pressure or the amount of gas, what is the new volume, \(V_2\), of the gas?
*Express the volume numerically in liters.*
[Input Box for \(V_2 = \)]
*Submit Button*
**Part B:**
What Celsius temperature, \(T_2\), is required to change the volume of the gas sample in Part A \((T_1 = 2 \,^\circ\text{C}, V_1 = 1330 \,\text{L})\) to a volume of \(2660 \,\text{L}\)? Assume no change in pressure or the amount of gas in the balloon.
*Express the temperature numerically in degrees Celsius.*
[Input Box for \(T_2 = \)]
*Submit Button*
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![**MasteringChemistry: Chapter 8 Introduction to Gases - Attempt 1**
# Temperature and Volume
**Charles's Law** states that the volume of a gas is directly related to the absolute temperature when there is no change in the pressure or amount of gas. This can be represented mathematically as:
\[
\frac{V_1}{T_1} = \frac{V_2}{T_2}
\]
**Figure 1 Explanation:**
The figure depicts two images of a cylinder with pistons. In the image on the left, labeled "Lower temperature, Smaller volume," the gas molecules are closer together, indicating a smaller volume. There is a small flame underneath the cylinder. The right image, labeled "Higher temperature, Larger volume," shows the gas molecules more spread out after an increase in temperature, indicating a larger volume due to heating. The flame underneath is the same size as in the left image.
**Problem Statement:**
**Part A:**
A sample of gas in a balloon has an initial temperature of \(2 \, ^\circ\text{C}\) and a volume of \(1330 \, \text{L}\). If the temperature changes to \(80 \, ^\circ\text{C}\), with no change in pressure or the amount of gas, what is the new volume, \(V_2\), of the gas?
*Express the volume numerically in liters.*
[Input Box for \(V_2 = \)]
*Submit Button*
**Part B:**
What Celsius temperature, \(T_2\), is required to change the volume of the gas sample in Part A \((T_1 = 2 \,^\circ\text{C}, V_1 = 1330 \,\text{L})\) to a volume of \(2660 \,\text{L}\)? Assume no change in pressure or the amount of gas in the balloon.
*Express the temperature numerically in degrees Celsius.*
[Input Box for \(T_2 = \)]
*Submit Button*](https://content.bartleby.com/qna-images/question/fe7bd5a3-664e-4976-a633-316155fccc96/79f96850-711f-4889-bc15-d11c58db9526/uy3ki49_processed.png)
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