Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- The 60 kg two-wheeled cart is described in the figure and parameter table below, with G indicating the location of the center of gravity. It is to be pulled so that it goes up the small step. Find the normal force on each wheel, and the magnitude and direction of the force applied at handle. HINT: remember that there are two wheels sharing the load @080 BY NO SA 2021 Cathy Zupke 4₁1 G L₁ L₂ parameter value 0.6 0.5 0.8 0.7 0.2 A L3 LA d L3 units m m m m m B L₂ F For the answers, take to the right and up to be the positive directions. The normal force at each wheel at A in the x direction is Ax= 150 XN The magnitude of the force at B is F Measured from the positive horizontal axis, the angle of F= 45 X° = 212 XNarrow_forwardThe uniform 16-kg plate is welded to the vertical shaft, which is supported by bearings A and B. Calculate the magnitude of the force supported by bearing B during application of the 100-N-m couple to the shaft. The cable from C to D prevents the plate and shaft from turning and the weight of the assembly is carried entirely by bearing A. 220 mm: 100 N-m) B 170 mm 80 mm 600 mm D 480 mmarrow_forwardA person is performing slow arm curls with 10-kgWeight as idicated in the left image of the figure below. The biceps group (consisting of the biceps and brachialis muscles) is the major factor in this exercise. Determine the magnitude F7 of the biceps group force and the magnitude 4 of the elbow joint reaction at point E for the forearm position. The free body diagram is shown in the right image of the figure. Take the dimensions shown to locate the effectivepoints of application of the biceps group; these points are 200 mm directly above E and 50 mm directly to the right of E. Include the eftect of the the 1.5-kg forearm mass with mass center at point G. Assuming that humerus is perfectly vertical and fixed; therefore, the elbow joint E is acting like pin connection. The forearm (E-B-G-C) is perfectly horizontal; therefore, the angle A-E-B is 90 deg.arrow_forward
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