Chapter 1110)Are low-fat diets or low-carb diets more effective for weight loss? A sample of 76 subjectswent on a low-carbohydrate diet for six months. At the end of that time, the sample mean weightloss was 4.6 kilograms with a sample standard deviation of 7.07 kilograms. A second sample of78subjects went on a low-fat diet. Their sample mean weight loss was 2.6 kilograms with astandard deviation of 5.83 kilograms. Can you conclude that the mean weight loss of subjectshaving low-carb diets is less than the mean weight loss of subjects having low-fat diets? Use0.01 level(a)State the appropriate null and alternate hypotheses.(b)Compute the P-value.(c)Determine whether to reject Null hypothesis(d)State a conclusion.11

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Insurance Company A claims that its customers pay less for car insurance, on average than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 11 people who buy insurance from Company A, the mean cost is $⁢150 per month with a standard deviation of $⁢14. For 14 randomly selected customers of Company B, you find that they pay a mean of $⁢158 per month with a standard deviation of $⁢12. Assume that both populations are approximately normal and that the population variances are equal to test Company A’s claim at the 0.10 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.
You wish to evaluate the differences in educational quality between two training centres (A and B). You take a random sample of 98 individuals trained at centre A, and an independent random sample of 41 individuals trained at centre B. The individuals in both samples take the same, standardised test. The mean test score of individuals in sample A is 85.1 and the sample standard deviation is 12.2. The mean test score in sample B is 67.4 and the sample standard deviation is 11.0. Find the lower limit of a 98% confidence interval for the difference between the population means. Form the confidence interval around a positive point estimate for the difference between the means. In order to obtain a positive point estimate, make sure you subtract the lower value from the higher value when calculating the difference between the sample means. (Provide your answer as a number rounded to 2 decimal places.)
Insurance Company A claims that its customers pay less for car insurance, on average, than customers of its competitor, Company B. You wonder if this is true, so you decide to compare the average monthly costs of similar insurance policies from the two companies. For a random sample of 13 people who buy insurance from Company A, the mean cost is $150 per month with a standard deviation of $19. For 9 randomly selected customers of Company B, you find that they pay a mean of $157 per month with a standard deviation of $16. Assume that both populations are approximately normal and that the population variances are equal to test Company A's claim at the 0.05 level of significance. Let customers of Company A be Population 1 and let customers of Company B be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
Participants were enrolled in a health-coaching program for eight weeks to try to improve physical health and overall wellness. At the end of the trial period, the participants take a personal health improvement survey. The mean health improvement survey score for all participants in the program was 74.4 with a standard deviation of 10.3. We have reason to think that one of the health coaches (Coach A) who participated in an additional training program will have subjects who have higher health improvement survey scores than the overall program average. We know that Coach A trains 30 subjects with the average health improvement survey score of 80.1. a) We want to test the hypothesis that subjects who work with Coach A have higher health improvement survey scores compared with the rest of the program participants. Use alpha of 0.05 b) Suppose a continuous random variable can only take on values between −1 and +1 on a standard normal curve, what is the area under the curve? Use…
According to the College Board, scores on the math section of the SAT Reasoning college entrance test for the class of 2010 had a mean of 516 and a standard deviation of 116. Assume that they are roughly normal.One of the quartiles of the scores from the math section of the SAT Reasoning test is 438. The other quartile is _______.
Steve believes that his wife's cell phone battery does not last as long as his cell phone battery. On eleven different occasions, he measured the length of time his cell phone battery lasted and calculated that the mean was 16.4 hours with a standard deviation of 6.4 hours. He measured the length of time his wife's cell phone battery lasted on seven different occasions and calculated a mean of 23.3 hours with a standard deviation of 4.2 hours. Assume that the population variances are the same. Let Population 1 be the battery life of Steve's cell phone and Population 2 be the battery life of his wife's cell phone. Step 1 of 2: Construct a 90 % confidence interval for the true difference in mean battery life between Steve's cell phone and his wife's. Round the endpoints of the interval to one decimal place, if necessary.
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The amount of money raised by Clayton State teams for the Statistics Games is normally distributed, with a mean of $360 and a standard deviation of $15. Using the Empirical Rule, approximately what proportion of teams raise more than $375?
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