As a result of the reaction with 100% yield, 11.4 mL of glycerol was obtained. How many grams of sodium hydroxide, which was completely spent, reacted? CH2-0-C-(CH2)14-CH3CH2-OHCH--(CH)14-CH3 + 3 NaOH-O-CH-OH + 3 Na0-C-(CH)14-CH3Sodium palmitate(a soap)CH2-O--(CH);-CH;CH;-OHTriglycerideGlycerolMw= 40 g/molMw=92,1 g/molMw=278,4 g/molMw=176,12 g/molO=U

GIven: The yield of the reaction given is 100% The volume of Glycerol obtained = 11.4 ml The density…

Answered: CH-0-C-CH2)14-CH3 CH;-OH (CH)4-CH, + 3…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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As a result of the reaction with 100% yield, 11.4 mL of glycerol was obtained. How many grams of sodium hydroxide, which was completely spent, reacted?

CH2-0-C-(CH2)14-CH3
CH2-OH
CH-
-(CH)14-CH3 + 3 NaOH
-O-
CH-OH + 3 Na0-C-(CH)14-CH3
Sodium palmitate
(a soap)
CH2-O-
-(CH);-CH;
CH;-OH
Triglyceride
Glycerol
Mw= 40 g/mol
Mw=92,1 g/mol
Mw=278,4 g/mol
Mw=176,12 g/mol
O=U

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