Cells manage to synthesize a variety of seemingly thermodynamically unfavored molecules every day. Phosphorylated glucose is an example of one of these molecules. The direct phosphorylation reaction is depicted below. As indicated, the forward reaction is unfavorable with a positive standard free energy change:   glucose + phosphate⇄ glucose-6- phosphate + water                              ΔG°’ = +14 kJ/mol   Describe specifically a thermodynamically favorable route by which the cell can produce glucose-6- phosphate from glucose. Please note cells cannot change either the temperature or the pressure at which the reaction is occurring. Please help me understand by using steps. Thank you!

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