Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.52 cm. If the potential difference across the plates was 23.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.

An electron is to be accelerated in a uniform electric field having a strength of 2.3·106  Vm. a)    What energy in keV is given to the electron if it is accelerated through 0.35 m? b)    Over what distance (in km) would it have to be accelerated to increase its energy by 58 GeV?

Review Multiple-Concept Example 4 to see the concepts that are pertinent here. In a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 24000 V. The speeds of the electrons are quite large, and for accurate calculations of the speeds, the effects of special relativity must be taken into account. Ignoring such effects, find the electron speed just before the electron strikes the screen. VB i eTextbook and Media GO Tutorial Save for Later Attempts: 0 of 6 used Submit Answer

An evacuated tube uses an accelerating voltage of 30 kV to accelerate electrons to hit a copper plate and produce X-rays. Non-relativistically, what would be the maximum speed (in m/s) of these electrons? 3.25E-07 × m/s

Consider a parallel-plate capacitor constructed of two square plates, 4.22 m on a side, separated by a distance 6.23 mm. If a charge of 2.85 nC is placed on one plate, with an equal but opposite charge on the other plate, find the electric field inside the capacitor. Answer in units of V/m.

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.56 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.   ????V/m

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.32 cm. If the potential difference across the plates was 24.0 kV, find the magnitude of the electric field (in V/m) in the region between the plates.

Two 2.2-cm-diameter-disks spaced 1.9 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.9×105 V/m. What is the voltage across the capacitor? How much charge is on each disk? An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×107 m/s . What was the electron's speed as it left the negative plate?

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.30 cm. If the potential difference across the plates was 25.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.                       V/m

A proton (m=1.67 x 10^-27 kg) travels a distance of 4.3 cm parallel to a uniform electric field 3.5 x 10^5 V/m between the plates shown in the figure. If the initial velocity is 3.2 x 10^5 m/s, find the magnitude of its final velocity in m/s. (Ignore gravity)