Categorize each molecule according to its hydrogen-bonding characteristics. Drag the appropriate items to their respective bins. View Available Hint(s) Reset Help CH3CH2NH2 CH3OCH3 CH3OH CH3CH2CH3 CH2=CH2 N(CH3)3 H₂O CH3C(O)CH3 no hydrogen bonding capability can be a hydrogen bond acceptor but not a hydrogen bond donor can be a hydrogen bond acceptor and a hydrogen bond donor

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Which of the following molecules would be the least polarizable? CH3CH2CH3 O SİH3SIH3 O CH3CH3 O SİH3SIH2SİH3 All of these are equally polarizable.

The bond dissociation energy to break 2 C-C bond(s) in 1 mole of glycerol (HOCH2CH(OH)CH2OH, see image below) molecules is H -C H- Single Bond H C N H 432 411 346 N 386 305 167 459 358 201 142 C=C 602 C=0 799 Multiple C=C 835 C=0 1072 Bonds 615 494 C=N O=0 CEN 887 N=N 942 "Al vales in ka

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19. Based on molecular mass and dipole moment of the five compounds in the table below, which one should have the highest boiling point? Dipole Moment (D) Substance Molecular Mass (amu) Propane, CH3CH2CH3 Dimethyl ether, CH3OCH3 Methylchloride, CH3C1 Acetaldehyde, CH;CHO Acetonitrile, CH3CN 44 0.1 46 1.3 50 1.9 44 2.7 41 3.9 B) CH;CN E) CH3CH2CH3 C) CH3CHO A) CH3OCH3 D) CH;CI

Please draw the two intermediates A and Cand then predict the products from the given reaction B and D, showing all potential products (including stereoisomers if they exist). Short3.png + (48KB)

In a sample of bonds in the position. (Note: Remember that iodine () is larger and more likely to contribute to steric strain in the molecule.) iodocyclohexane (CH), one would expect to find most of the C-I O equatorial O trigonal pyramidal O tetrahedral Oplanar O axial Question 7 The molecule aniline is pictured here. Which of the following words could be used to describe an essential feature of aniline to someone who is familiar with chemistry, but not with this molecule? O aromatic O heterocycle O non-cyclic fused-ring system O alkane NH₂

Which of the following statements are TRUE for covalent pi bonds? (Choose as many as apply. Hint: There are 4 correct answers!) Pi bonds arise from head-on overlap of two orbitals. Pi bonds arise from sideways overlap of two orbitals. The electron density in a pi bond is found above and below the axis between the two bonded nuclei. The electron density in a pi bond is found in between the two bonded nuclei. A pi bond can exist independently; not every pi bond is accompanied by an associated o bond. Pi bonds always exist in conjunction with an associated o bond; they can never exist independently. The pi bonds in a molecule determine the shape of the molecule. There can be more than one pi bond between two nuclei. Every covalent bond contains at least one pi bond.