Carbon tetrachloride (CCl4) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.09 x 10-2 kg/m³, and the diffusion constant is 23.4 x 10-10 m²/s. The CCl4 enters the tube at a mass rate of 4.38 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A. 5.00 x 10-³ m -CCI4 Cross-sectional area = 3.00 x 10-4 m²

Carbon tetrachloride (CCl4) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.09 x 10-2 kg/m³, and the diffusion constant is 23.4 x 10-10 m²/s. The CCl4 enters the tube at a mass rate of 4.38 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A. 5.00 x 10-³ m -CCI4 Cross-sectional area = 3.00 x 10-4 m²

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter16: Temperature And The Kinetic Theory Of Gases

Section: Chapter Questions

Problem 39P

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