Can you show how 184 appear? This is the problem:The beam shown in figure is 5 inches wide and 10 inches deep. What is the maximum bending stress? R= 300(14)= 4200 Ibs342000 Ibs300 b/tRI 2284R2 = 3916%3D5 ftftft2284Ancimpta= 2284(5)= 11,420Anpenid = % (2284 +184)(7)= 8,638184A = 11,420 +8,638= 20,05818161°2005811420-39162°19(4200+2000)(12)%3DR2 (19)R, +3916= 4200+2000R2 = 3916 ibsR, = 2284 bsRefer to the shear and moment diagram: Mm = 20058 b-ft 240,696 lb-inA = 5(10) = 50 in?N.A.10 inbh 5(10)416.7 in5 in1212Mс (240,696X5)O bending416.7Opending = 2888.1 psi

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Answered: Can you show how 184 appear? This is…

Can you show how 184 appear? This is the problem: The beam shown in figure is 5 inches wide and 10 inches deep. What is the maximum bending stress?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Can you show how 184 appear? This is the problem:

The beam shown in figure is 5 inches wide and 10 inches deep. What is the maximum bending stress?

R= 300(14)= 4200 Ibs
34
2000 Ibs
300 b/t
RI 2284
R2 = 3916
%3D
5 ft
ft
ft
2284
Ancimpta= 2284(5)
= 11,420
Anpenid = % (2284 +184)(7)
= 8,638
184
A = 11,420 +8,638
= 20,058
1816
1°
20058
11420
-3916
2°
19
(4200+2000)(12)%3DR2 (19)
R, +3916= 4200+2000
R2 = 3916 ibs
R, = 2284 bs
Refer to the shear and moment diagram:

Mm = 20058 b-ft 240,696 lb-in
A = 5(10) = 50 in?
N.A.
10 in
bh 5(10)
416.7 in
5 in
12
12
Mс (240,696X5)
O bending
416.7
Opending = 2888.1 psi

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