
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Topic Video
Question
Can you check my homework? Im sure I got the right answer, would the force of the tibia be -2984N instaead of positive? thank you
![### Educational Content on Foot Biomechanics
#### Problem Statement
A person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has a magnitude of 750 N. Ignore the weight of the foot itself. The other significant forces acting on the foot are the tension in the Achilles tendon pulling up and the force of the tibia pushing down on the ankle joint.
#### Diagram Explanation
The accompanying diagram illustrates the forces acting on the foot:
- **Achilles Tendon**: The diagram shows the Achilles tendon exerting an upward force shown by an arrow labeled \( F_{\text{Achilles}} \).
- **Tibia**: An arrow labeled \( F_{\text{tibia}} \) is depicted exerting a downward force on the ankle joint.
- **Normal Force**: An arrow labeled \( N \) indicates the normal force exerted by the ground, pointing upward.
- **Anatomy of Foot**:
- **Tibia**: Bone labeled in the upper part of the leg.
- **Calcaneus (heel bone)**: Depicted at the bottom of the foot, where the normal force \( N \) acts.
- **Gastrocnemius-soleus muscles**: Shown connected to the Achilles tendon.
#### Question
If the tension in the Achilles tendon is 2234 N, what is the force exerted on the foot by the tibia? If the force is upward, enter a positive value. If the force is downward, enter a negative value.
**Calculation:**
Given:
- Tension in the Achilles tendon \( T_{\text{Achilles}} \) = 2234 N (upward)
- Normal force \( N \) = 750 N (upward)
To find the force exerted by the tibia \( F_{\text{tibia}} \), we use the equilibrium condition. For vertical forces to balance:
\[ F_{\text{tibia}} + T_{\text{Achilles}} - N = 0 \]
\[ F_{\text{tibia}} + 2234 - 750 = 0 \]
\[ F_{\text{tibia}} = 750 - 2234 \]
\[ F_{\text{tibia}} = -1484 \]
So, the force exerted on the foot by the tibia is **-1484 N (downward)**.
However,](https://content.bartleby.com/qna-images/question/ff7f72a6-27ca-4fc6-a195-84c52d046220/17c1afcd-f628-4e9c-a67a-46c612d3914c/eunsio3_thumbnail.jpeg)
Transcribed Image Text:### Educational Content on Foot Biomechanics
#### Problem Statement
A person stands on the ball of one foot. The normal force due to the ground pushing up on the ball of the foot has a magnitude of 750 N. Ignore the weight of the foot itself. The other significant forces acting on the foot are the tension in the Achilles tendon pulling up and the force of the tibia pushing down on the ankle joint.
#### Diagram Explanation
The accompanying diagram illustrates the forces acting on the foot:
- **Achilles Tendon**: The diagram shows the Achilles tendon exerting an upward force shown by an arrow labeled \( F_{\text{Achilles}} \).
- **Tibia**: An arrow labeled \( F_{\text{tibia}} \) is depicted exerting a downward force on the ankle joint.
- **Normal Force**: An arrow labeled \( N \) indicates the normal force exerted by the ground, pointing upward.
- **Anatomy of Foot**:
- **Tibia**: Bone labeled in the upper part of the leg.
- **Calcaneus (heel bone)**: Depicted at the bottom of the foot, where the normal force \( N \) acts.
- **Gastrocnemius-soleus muscles**: Shown connected to the Achilles tendon.
#### Question
If the tension in the Achilles tendon is 2234 N, what is the force exerted on the foot by the tibia? If the force is upward, enter a positive value. If the force is downward, enter a negative value.
**Calculation:**
Given:
- Tension in the Achilles tendon \( T_{\text{Achilles}} \) = 2234 N (upward)
- Normal force \( N \) = 750 N (upward)
To find the force exerted by the tibia \( F_{\text{tibia}} \), we use the equilibrium condition. For vertical forces to balance:
\[ F_{\text{tibia}} + T_{\text{Achilles}} - N = 0 \]
\[ F_{\text{tibia}} + 2234 - 750 = 0 \]
\[ F_{\text{tibia}} = 750 - 2234 \]
\[ F_{\text{tibia}} = -1484 \]
So, the force exerted on the foot by the tibia is **-1484 N (downward)**.
However,
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps with 1 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Kindly provide the answer in three significant figures, and the tolerance is ±1 in the 3rd significant digit. 550.28 is incorrect. Thank you!arrow_forwardConsider the figure below. (a) Find the tension in each cable supporting the 604-N cat burglar. (Assume the angle 0 of the inclined cable is 31.0°.) inclined cable horizontal cable vertical cable (h Suppose the horizontal cable were reattached higher up on the wall. Would the tension in the inclined cable increase, decrease, or stay the same? O increase O decrease O stay the same NNNarrow_forwardNeeds Complete typed solution with 100 % accuracy.arrow_forward
- Needs Complete typed solution with 100 % accuracy.arrow_forwardThe mass of the block = 172 kg First Force applied, Fapp 1 = 225.1 N Second Force applied, Fapp 2 = 330.2 N Find the Normal Force, Fnarrow_forwardAs shown in the figure, the mass of the block is 214 kg. If Fappi= 59.4 N and Fapp2=38.7 N, find the normal force. Fapp. Fopps FRarrow_forward
- On a roller coaster ride the total mass of a cart - with two passengers included - is 268 kg. Peak K is at 43.2 m above the ground and peak L is at 26.0 m. At location K the speed of the cart is 17.2 m/s, and at location L it is 12.5 m/s. (The wheel mechanism on roller coaster carts always keeps the carts safely on the rail.) K How much mechanical energy is lost due to friction between the two peaks? Submit Answer Tries 0/10arrow_forwardPlease ans all parts, as it's 1 questionarrow_forwardIndicate all forces on the following system: make sure to label as well.arrow_forward
- Initially at rest H.arrow_forwardPlease show full solution, and in 5 sig figs. Thanks!arrow_forwardThe forces acting onan object weighingW units on aninclined planepositioned at anangle of θ with thehorizontal (see figure)are modeled byμW cos θ = W sin θ,where μ is the coefficient of friction. Solve theequation for μ and simplify the result.arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON

College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning

University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press

Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning

Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley

College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON