Following are the results of a field unit weight determination test on a soil using the Sand Cone Method. Determine the field unit weight of the soil. FEEDBACK GUARANTEED Calibration:Determination of mass of sand to fill the cone:Mass of jar + cone + sand (before use) = 6.25 kgMass of jar + cone +sand (after use) = 6.09 kgDetermination of dry density of the sand:Mass of jar + cone + sand (before use) = 6.28 kgMass of jar + cone + sand (after use) = 4.62 kgVolume of the mold=943.333 cm³Determination of the field unit weight:Mass of jar + cone + sand (before use) = 6.27 kgMass of jar + cone + sand (after use) = 3.18 kgMass of excavated moist soil from the hole = 3.58kgMoisture content of the moist soil = 11.24%Field Test:

Solution Given: Calibration: Weight of Jar + Cone + Sand (before use), W1=6.25kg Weight of Jar +…

Calibration: of mass of sand to fill the cone: Mass of jar + cone + sand (before use) = 6.25 kg Mass of jar + cone +sand (after use) = 6.09 kg Mass of jar + cone + sand (before use) = 6.28 kg Mass of jar + cone + sand (after use) = 4.62 kg Volume of the mold = 943.333 cm³ Mass of jar + cone + sand (before use) = 6.27 kg Mass of jar + cone + sand (after use) = 3.18 kg Mass of excavated moist soil from the hole = 3.58 kg Moisture content of the moist soil = 11.24% Determination Determination of dry density of the sand: Field Test: Determination of the field unit weight:

Calibration: of mass of sand to fill the cone: Mass of jar + cone + sand (before use) = 6.25 kg Mass of jar + cone +sand (after use) = 6.09 kg Mass of jar + cone + sand (before use) = 6.28 kg Mass of jar + cone + sand (after use) = 4.62 kg Volume of the mold = 943.333 cm³ Mass of jar + cone + sand (before use) = 6.27 kg Mass of jar + cone + sand (after use) = 3.18 kg Mass of excavated moist soil from the hole = 3.58 kg Moisture content of the moist soil = 11.24% Determination Determination of dry density of the sand: Field Test: Determination of the field unit weight:

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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SURFACE MOISTURE OF FINE AND COARSE AGGREGATE Pycnometer or Flash Method make up computation, make one Mass of specimen (S) Mass of pycnometer + water (C) Mass of pycnometer + water + specimen (W) Mass of displaced water (V) Specific Gravity, G 2.86 D = S/G % surface moisture
Three samples of aggregates were taken weighed in moist and dry condition. Moist Dry Unit Absorption Volume (m3) Unit Aggregate Wt. Wt. (%) (kN/m3) (kN/m3) Sample 1 23.425 20.018 5.14 0.366 Sample 2 22.7 18.757 3.87 0.695 Sample 3 20.292 18.387 2.62 0.237 Where; Unit weight of water = 9.81 kN/m3 %3D Determine the average free moisture content of the three samples.
Q2 (a) A specific gravity test was performed on a sample of fine aggregate and produced the following results: Mass of sand (saturated surface dry) = 520g Mass of sand (oven dry) = 510g Mass of pycnometer with full of water = 1550g Mass of pycnometer with sand and water = 1900g
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = ½ ft³ Weight of empty bucket = 20.3 lb Weight of bucket filled with dry rodded coarse aggregate Trial 1 = 69.6 lb Trial 2 = 68.2 lb Trial 3 = 71.6 lb a. Calculate the average dry-rodded unit weight b. If the bulk dry specific gravity of the aggregate is 2.620, calculate the per- cent voids between aggregate particles for each trial.
Table below shows the result of sieve analysis test on a sample of fine aggregate. What is the fineness modulus for this aggregate? Sieve size, mm 9.5 4.75 2.36 1.18 0.6 0.3 0.2 0.15 Percent passing 100 89 61 29 18 14 10 9 3.30 3.20 320 330
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Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 12 ft3Weight of empty bucket = 20.3 lbWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 76.6 lbTrial 2 = 75.1 lb Trial 3 = 78.8 lba. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
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