Calculation: For center Loading: MR = 3PL / 2bd? Where: MR- modulus of rupture, psi (MPa) P= maximum load applied as indicated by testing machine, in Ib (N) L= span length, in inches (mm) b= average width of specimen in inches (mm) d= average depth of specimen, at the fracture, in inches (mm) Note: The weight of the beam is not included in the above calculation. Tabulated Data and Result Sample No. L (mm) В (mm) D (mm) P (N) MR (MPa) 1 450 150 150 23000 450 150 150 21000 3 450 150 150 19000

Problem 1.4. A tensile test was conducted on a mild steel bar. The following data was obtained from the test : (i) Diameter of the steel bar (ii) Gauge length of the bar (iii) Load at elastic limit (iv) Extension at a load of 150 kN. (v) Maximum load (vi) Total extension (vii) Diameter of the rod at the failure Determine : (a) the Young's modulus, = 3 cm = 20 cm = 250 kN = 0.21 mm = 380 kN = 60 mm - 2.25 cm. (c) the percentage elongation, and (b) the stress at lastic limit, (d) the percentage decrease in area.

A 42 meter solid shaft is under torsional loading 53 Nm. If in this application, the allowable shear stress for the material is 369 MPa.    Calculate the required minimum diameter of the shaft: _____ mm ( input the value directly from your calculation before rounding it up to an engineering accepted diameter) Pay attention to units, and calculate your answer to one decimal place.

2 please include scketch