Calculating the pH of a weak base titrated with a strong acid An analytical chemist is titrating 186.4 mL of a 0.2900 M solution of dimethylamine ((CH3), NH) with a 0.3600 M solution of HNO3. The p K, of dimethylamine is 3.27. Calculate the pH of the base solution after the chemist has added 70.4 mL of the HNO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO, solution added. Round your answer to 2 decimal places. olo pH Ar

A buffer is made using 100.0 mL of 0.100 M CH3CH2COOH (propanoic acid) and 100.0 mL of 0.100 M NaCH3CH2COO (sodium propanoate). 10.0 mL of 0.100 M HCl is added to the buffer. What is the solution pH after the HCl is added?For CH3CH2COOH K = 1.3 x 10^-5

A chemistry graduate student is given 300. mL of a 1.60M pyridine (C H,N) solution. Pyridine is a weak base with K,=1.7 × 10 What mass of CH,NHC1 should the student dissolve in the CH,N solution to turn it into a buffer with pH = 5.16? You may assume that the volume of the solution doesn't change when the CH,NHCI is dissolved in it. Be sure your answer has a unit symbol, and round it to 2 significant digits.

A chemistry graduate student is given 250. mL of a 1.40M trimethylamine ((CH,) N) solution. Trimethylamine is a weak base with K, =7.4 × 10 *. What 3 mass of (CH,) NHCI should the student dissolve in the (CH, N solution to turn it into a buffer with pH =10.85? 3 You may assume that the volume of the solution doesn't change when the (CH,) NHC1 is dissolved in it. Be sure your answer has a unit symbol, and round it to 2 significant digits. olo x10 Ar ? Explanation Check © 2022 McGraw Hill LLC. AlL Rights Reserved. Terms of Use | Privacy Center | Accessibility

O ACIDS AND BASES Calculating the pH of a weak base titrated with a strong acid with a 0.3000 M solution of HNO,. The p K, of An analytical chemist is titrating 160.2 mL of a 0.5000 M solution of dimethylamine ((CH₂)2NH) w dimethylamine is 3.27. Calculate the pH of the base solution after the chemist has added 280.8 mL of the HNO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO, solution added. Round your answer to 2 decimal places... PH-0 X

A chemistry graduate student is given 300. mL of a 1.30M hydrocyanic acid (HCN) solution. Hydrocyanic acid is a weak acid with K = 4.9 × 10 mass of KCN should the student dissolve in the HCN solution to turn it into a buffer with pH=9.51? -10 . What You may assume that the volume of the solution doesn't change when the KCN is dissolved in it. Be sure your answer has a unit symbol, and round it to 2 significant digits. Explanation 81°F Mostly sunny Check $ 0.0 X с с % S F6 Q Search F7 FB F9 F10 © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | A e c (4) D F11 *+ D F12 PrtSc Insert Delete

A chemistry graduate student is given 300. mL of a 1.60 M benzoic acid (HC¸H,CO,) solution. Benzoic acid is a weak acid with K,=6.3 × 10¯°. what mass of NaC,H,CO, should the student dissolve in the HC H,CO, solution to turn it into a buffer with pH =3.68? 9. You may assume that the volume of the solution doesn't change when the NaC¸H¸CO, is dissolved in it. Be sure your answer has a unit symbol, and round it 6° 2 to 2 significant digits.

An analytical chemist is titrating 74.8 mL of a 0.5300 M solution of butanoic acid (HC,H,CO,) with a 1.200 M solution of KOH. The p K, of butanoic acid is 4.82. Calculate the pH of the acid solution after the chemist has added 36.1 mL of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal places.

An analytical chemist is titrating 122.9 mL of a 0.6300M solution of isopropylamine ((CH,) CHNH,) with a 0.3800M solution of HNO3. The p K, of 2 isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 233.4 mL of the HNO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO, solution added. 3. Round your answer to 2 decimal places.

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