Calculate ΔrH° (in  kJ mol−1), ΔrS° (in J K−1 mol−1),  ΔrG° (in kJ mol−1) at 298.15 K for the reaction below.       C(gr.) + 12 N2(g) + 52 H2(g) ⟶ CH3NH2(g) ΔfH ° at 298.15 K / kJ mol−1 0   0   0   −22.97 S¯ ∘at 298.15 K / J K−1 mol−1 5.74   191.61   130.68

3) For the phase change Br2(1) → Br2 (g), AH°= +31.0 kJ/mol and AS°= +92.9 J/mol.K. Assuming that AH° and AS° are nearly temperature independent, calculate the approximate Celcius temperature at which Br2(1) will be in equilibrium with Br2(g) at 1 atm.

For the reaction Fe,O3(s) + 3H2(g)–2Fe(s) + 3H,O(g) AH° = 98.8 kJ and AS° = 142.5 J/K %3D The equilibrium constant for this reaction at 345.0 K is Assume that AH° and AS° are independent of temperature.

Using enthalpies of formation, calculate deltaH for the following reaction at 25°C. Also calculate deltaS for this reaction from standard entropies at 25°C. Use these values to calculate deltaG for the reaction at this temperature. Species  deltaHf(kJ/mol)  S(J/mol⋅K) CH3OH(l) –238.7 126.8 O2(g) 0 205.0 CO2(g) –393.5 213.7 H2O(l) –285.8 69.95 2CH3OH(l) +3O2(g) --- 2CO2(g) + 4H2O(l) deltaH =  kJ deltaS =  J/K deltaG =  kJ

What is the change in Gibbs Free Energy (in k/J/mol) for a reaction that has the following thermodynamic values at 77.7 Celisus : Delta H rxn = -307.7 kJ/mol and delta H = 340.6 J mol negative 1 K negative 1?

Calculate ΔH° for the process Sb(s) + 52Cl2(g) ⟶ SbCl5(s) from the following information: Sb(s) + 32Cl2(g) ⟶ SbCl3(s) ΔH° = −314 kJ SbCl3(s) + Cl2(g) ⟶ SbCl5(s) ΔH° = −80 kJ

The pressure dependence of G is quite different for gases and condensed phases. Calculate ΔGm for the process (C,solid,graphite,1bar,298.15K)→(C,solid,graphite,300.bar,298.15K) The density for graphite is 2250 kg⋅m−3 Calculate ΔGm for the process (He,g,1bar,298.15K)→(He,g,300.bar,298.15K)

Calculate the ΔGo for X, in kJ, from the data given below at 327 K:   2X(g) → X2(g)     So (J/mol-K) ΔHo (kJ/mol) X(g) 51.2 77.4 X2(g) 61.4 171.1

What is ΔrH for a reaction that has ΔrG = 48.5 kJ mol-1 and ΔrS = -12.3 J mol-1 K-1 at -16.6 °C? Express your answer in kJ mol-1 .     ( Please type answer note write by hend )