Calculated he angular acceleration of the cylinder? Part B)if instead of Force F an actual mass m = 0.750 kg is hung from the string, find the angular acceleration of the cylinder? Part C) how far does m travel downward between 0.450 s and 0.650s after the motion begins Part D) the cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.344 m in a time of 0.490 s. find Icm of the new cylinder?

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Part A) M, a solid cylinder (M=2.27 kg, R=0.137 m) pivots on a thin, fixed, frictionless bearing. A String wrapped around the cylinder pulls downward with a force F which equals the weight of 0.750kg mass, i.e., F=7.357N. Calculated he angular acceleration of the cylinder? Part B)if instead of Force F an actual mass m = 0.750 kg is hung from the string, find the angular acceleration of the cylinder? Part C) how far does m travel downward between 0.450 s and 0.650s after the motion begins Part D) the cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.344 m in a time of 0.490 s. find Icm of the new cylinder?
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M, a solid cylinder (M=2.27 kg, R=0.137
downward with a force F which equals th
R
M
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Transcribed Image Text:Safarl File Inbox (1) - jennfossee@gmail.com section: AP_per6) Madelin Isabel Amato (Student Main Menu Contents Grades Feeds Course Contents » AP1 - Torque and Rotational M, a solid cylinder (M=2.27 kg, R=0.137 downward with a force F which equals th R M Submit Answer Tries 0/99
Inbox (1) - jennfossee@gmail.com
Submit Answer
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If instead of the force F an actual mass m
M
m
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Transcribed Image Text:Inbox (1) - jennfossee@gmail.com Submit Answer Tries 0/99 If instead of the force F an actual mass m M m Submit Answer Tries 0/99
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