Calculate theoretical yield of the Grignard reaction synthesis of triphenylmethanol from bromobenzene. Amounts of products used are listed in the image.

QUESTION T5 Why were the areas underneath the peaks in the gan chromatographs you eobtained mutiplied by a weight tactor? DA the corrction factor compensates for user error OB Rame lonization detectors (FID) respond slightly dfferent to compounds with diferent molecular weights OCnone of the answers OD. the GC (GOW MAC 350) used contains a quadrapole mass spec detector whose response must be corrected for the miz ratio of the diferent ions obtainen for diferert moleculestune OE not all molecules have the same themmal conductivity QUESTION 16 Which list of functional groups is present in the anti-viral drug Arbidol HO Br O A Thioether, alkene, ester, amide, amine O 8. Thioether alcohol, ester, amine OC Alcohol, ether, amide, epoxide, thioester OD. Ether, ketone olefin, amine, alcohol O E Thioalcohol, alkene, ether, amine, nitro

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119 X My Course X Macmillan: X Course Mo X What is the FORMULA for the limiting reagent? Submit Answer Sections 5 X .com/static/nb/ui/evo/index.html?deploymentid=5735112480241329813180832311&elSBN=9781305862883&id=1707786042&snapshoti... Use the References to access important valdes ir needed for this question. 900 For the following reaction, 9.43 grams of carbon (graphite) are allowed to react with 28.5 grams of oxygen gas. carbon (graphite) (s) + oxygen (g) carbon dioxide (g) What is the maximum amount of carbon dioxide that can be formed? What amount of the excess reagent remains after the reaction is complete? HOMEWOR X MacBook Air MindTap - C X GI grams grams

What is the key equation for spectrometry experiments? O q rxn = -q_cal %3D O d=m/V O A= ebC O at endpoint, mol acid = mol base

how do i calculate the Theoretical and % yield using this table?

overall aden fn tereactiorabwe! .20 what is te overall aae for tereactrobre! 200 0.00 8.00xl0 1. 0. 1000 200x1o? Trual A +BSAB On 12

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With correct sig figs

In a chromatography experiment, a solution containing 0.083 7 M X and 0.066 6 M S gave peak areas of AX = 423 and AS 5 347. (Areas are measured in arbitrary units by the instrument.) To analyze the unknown, 10.0 mL of 0.146 M S were added to 10.0 mL of unknown, and the mixture was diluted to 25.0 mL in a volumetric flask. This mixture gave the chromatogram in Figure 5-8, with peak areas AX = 553 and AS = 582. Find the concentration of X in the unknown.