Calculate the work done W by a closed system containing m= 1kg of steam, when it is compressed (a) from pA = 0.1 MPa to pB = 2.5 MPa, isothermally at T = 400C and; (b) from pA = 0.5 MPa to pB = 2.5 MPa, isothermally at T = 600C .  Use steam tables and the trapezoidal rule for integration

For first law thermodynamics , Q-W = E where E is the change in total energy. My question is when should we use q-w = h2-h1 when h is the change in epecific enthalpy and q-w = u2-u1 and  u isthe change in specific internal energy?

Please include the figure and complete solution. Thank you!

Q1/ A certain perfect gas for which(y=1.26) and The molar mas is (26 kg/k.mol) expunds reversibly From (727 C), (0.003m^3) to (2 C), (0.6m^3) Accordiy to a linear law on T-S digram Calculate the work don ber (kg) and sketch the T-S digram

Please show the complete solution. (Example: Unit of Conversion) Steam at 2 MPa and 250°C in a rigid cylinder is cooled until the quality is 30%. Find the heat rejected from the cylinder. @ 2 Mpa and 250°C: υ = 0.11144 m3 /kg                                       u = 2679.6 kJ/kg  @ 2 Mpa, (saturated):υf = 0.0011767 m3 /kg                                         υg = 0.09963 m3 /kg                                         uf = 906.44kJ/kg                                         ug = 1693.8 kJ/kg

Find the temperature of the following using the ideal gas law:(a) water, P=10KPa, v=30m^3/kg(b) water, P=10MPa, v=0.019m^3/kg

He gas undergoes adiabatic expansion at P1 = 8 bar, T1 = 750K to T2 = 400K. Then, the gas is heated at constant P back to T3 = 750K. If the process is to be replaced by a single isothermal expansion step to an arbitrary pressure P, what value of P (in bar) will result to the same work as the original process? Assume helium is an ideal gas with constant heat capacity.   a.1.56 b.0.90 c.2.49 d.1.66

E3.1. You must use the property data from the tables in the Appendix of your text to do this problem. The figure below illustrates a pressure cooker with the pressure relief valve removed. atm- 100 kPa V= 2 liter bottom 5% is filled with liquid water . The pressure cooker has an internal volume of V = 2 liters. Because the relief valve is removed, the contents are initially at atmospheric pressure, Patm = 100 kPa. The pressure cooker contains water in a two-phase state. The bottom 5% of the volume of the vessel is filled with liquid water while the remainder of the vessel contains water vapor. a) Determine the initial temperature of the water in the cooker. b) Determine the quality and specific volume of the water initially in the cooker. c) Sketch by hand a T-v diagram and label the initial state of the water (state 1).

L An iniially empty bottle is illed with water from a line at 0.8 MPa and 350-C. Assume that there is no heat transfer and that the bottle is closed when the pressure reaches the line pressure, If the final mass is 0.7 kg, find the final temperature and the volume of the botle.

There's a copper calorimeter container with the mass 0.2 kg and has 0.32 kg of H2O and also 0.036 kg of ice (thermal equilibrium at atm). If we drop 1.5 kg of lead at a temperature of 200 Celsius into calorimeter container, find the final temperature (in Celsius). Please show work Lead=131J/kgK Copper=390J/kg.K H2O = Cw = 4190 J/kg.K & LF = 3.34 x 105 J/kg