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I performed a lab using a toy car to go down a ramp that was positioned at different heights. For expample: ramp height = 40 cm, ramp length = 121.92 cm, time car took to clear the ramp from start = .86 seconds, distance car traveled from end of ramp to stopping point = 937.26 cm, mass of car = .54 kg, based off this information.....
Calculate the velocity of the car at the end of the ramp just before it starts its horizontal path to its stopping point. PE = KE = (1/2) m v^2
As per the conservation law of energy,
Here, E, K, and U represent the car’s total energy, the car’s kinetic energy, and the car’s potential energy, respectively.
Here, the subscript S and B represent the car’s position at the ramp’s top and ramp’s bottom, respectively.
The car’s kinetic energy can be represented as,
Here, m and v represent the car’s mass and the car’s velocity, respectively.
The car’s potential energy can be represented as,
Here h represents the car’s height from the ramp’s bottom.
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