Calculate the value of the cell potential, Ecell, for this reactión at 29 [1"] = 0.0050 M, and [Br2] = 1.0 M 12 (s) + 2 Br (aq) --> 21 (aq) + Br2 (aq) Note: The reaction shown above is the same as in the previous question; you'll need to use your answer to the previous question. EQUATIONS AND CONSTANTS E sell = E°cdll- (0.0592/n) log Q @ 25 °C R= 8.314 J/mol K AG a =-nFE°. F= 9.65 x 104 J/V•mol e cell AG rxn =-(RT)In K E"cell = (RT/nF) In K %3D For electrolysis: In (No/N) = kt 1A =1 C/s t12 0.693/k F = 9,65 x 104 C/mol e - 0.67 V + 0.99 V O + 0.23 V + 1.13 V - 0.45 V

Calculate the value of the cell potential, Ecell, for this reactión at 29 [1"] = 0.0050 M, and [Br2] = 1.0 M 12 (s) + 2 Br (aq) --> 21 (aq) + Br2 (aq) Note: The reaction shown above is the same as in the previous question; you'll need to use your answer to the previous question. EQUATIONS AND CONSTANTS E sell = E°cdll- (0.0592/n) log Q @ 25 °C R= 8.314 J/mol K AG a =-nFE°. F= 9.65 x 104 J/V•mol e cell AG rxn =-(RT)In K E"cell = (RT/nF) In K %3D For electrolysis: In (No/N) = kt 1A =1 C/s t12 0.693/k F = 9,65 x 104 C/mol e - 0.67 V + 0.99 V O + 0.23 V + 1.13 V - 0.45 V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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