Calculate the value of ?p for the equation C(s)+CO2(g)↽−−⇀2CO(g)?p=? given that at a certain temperature C(s)+2H2O(g) ⇀CO2(g)+2H2(g) ?p1=3.47 H2(g)+CO2(g) ↽−−⇀H2O(g)+CO(g)?p2=0.645

(D 263 kJ/mol P. 22. Using the following thermochemical equations: C(s) + O,(g) → CO,(g) ΔΗΟ. rxn 1 =-394 kJ/mol,Txn C(s) + CO,(g) → 2 CO(g) AH°. Ixn 2 =+173 kJ/mol,xa Determine the enthalpy of the reaction represented below: 2 C(s) + 0,(g) → 2 CO(g) ΔΗ Txn 3 = ? 1> (A) ΔΗ. :-567 kJ/molxn rxn (В) ДН =-221 kJ/mol,xn (С) ДН =+221 kJ/molpxn (D) AH°. +567 kJ/molpxn %3D Ixn qt ian od geind hw qua boalunai na cop d ofiosa orb d A 100--32 HO0-02 X convinn or rmrainn an nart of this nanA iR llanal.

Use the following information to determine the standard enthalpy change when 1.00 mol of PbO(s) is formed from lead metal and excess oxygen gas by the reaction 2Pb(s) + O2(g) PbO(s) PbO(s) + C(graphite) -Pb(s) +AH° = 107 kJ Co(g) 2C(graphite) + O2(g) -2CO(g) AH° = -222 kJ Select one: a. -115 kJ b. -218 kJ C. - 436 kJ d. -329 kJ e. +436 kJ

The internal pressure of a gas, π = au dv)T' is a measure of intermolecular forces, because it indicates a change in internal energy as the molecules get closer or further apart, without temperature changing. = a Calculate the change in internal 1 Vm T energy, AU, when 1.5 mols of acetone (a = 16 l² atm/mo1²), expands from 2 liters to 5 liters at a constant temperature. ii) Would this change in internal energy be greater or smaller for an ideal gas? Why? i) Using the van der Waals equation of state, T = au