Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Calculate the theoretical yield of MgCl2 in moles when 0.339 grams of MgO are reacted with 30.6 mL of 1.01 M HCl. The balanced reaction is provided in the lab handout. Do not enter units with your answer.
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- . Consider a 3.52-g sample of CaCO3 (99.87% pure) in a flask and a 100.0 mL sample of vinegar (5% acidity) in a graduated cylinder. The combined mass of both reagents and containers is 255.98 g. After swirling the reaction mixture for about twenty minutes, the combined mass of the reaction mixture and containers is found to be 254.46 g. What is the percent yield of carbon dioxide in this experiment?arrow_forward19. A product weighing 12.11 g was isolated/obtained in the laboratory. The maximum amount of obtainable product was calculated to be 20.51g. What is the percentage (%) yield of this reaction?arrow_forwardRefer to this equation: 3SCl2 + 4NaF --> SF4 + S2Cl2 + 4NaCl 64.0 grams SCl2 is reacted with excess NaF and 12.5 grams of SF4 is formed. What is percent yield SF4? Hint: find theoretical yieldHint: percent yield =(actual yield/ theoretical yield) x 100arrow_forward
- For the following reaction, 0.115 moles of aluminum oxide are mixed with 0.332 moles of sulfuric acid. aluminum oxide(s) + sulfuric acid(aq) → aluminum sulfate(aq) + water(l) What is the formula for the limiting reagent? What is the maximum amount of aluminum sulfate that can be produced? molesarrow_forward1.Given the following balanced chemical equation, how many grams of O2 would be produced from 21.44 g of Potassium chlorate? 2KClO3 --> 2KCl + 3O2 ________g O2 All work must be shown and submitted. Any steps left out may result in a loss of points for that particular problem. ALL UNITS AND LABELS MUST BE SHOWN THROUGHOUT THE PROBLEM, INCLUDING CANCELLING THEM WHEN APPROPRIATE. If units and/or labels are missing, 2 points will be deducted per problem.arrow_forwardUpon reaction of 1.27 gof copper sulfate with excess zinc metal, 0.239 g copper metal was obtained as an experimental result according to the equation: CuSOalaq) + Zn(s) Culs) + ZnSO.laq) Before the experiment was carried out the theoretical yield calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu. What is the percent yield in standard notation?arrow_forward
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