Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Problem Statement: Acid-Base Equilibrium and pH Calculation**

Calculate the pH of a solution prepared by dissolving 0.174 mol of *m*-chlorobenzoic acid (C₆H₄ClCOOH, Kₐ = 1.00×10⁻⁴) and 0.430 mol of hydrocyanic acid (HCN, Kₐ = 6.17×10⁻¹⁰) in water and diluting to 2.40 L. Also, calculate the equilibrium concentrations of C₆H₄ClCOOH, C₆H₄ClCOO⁻, HCN, and CN⁻. Do not make an approximation unless the initial acid concentration is greater than 1000 × Kₐ. (Hint: The pH will be determined by the stronger acid of this pair.)

**Calculations Required:**

- **pH**: [                   ]
  
- **Equilibrium Concentrations**:

  - [C₆H₄ClCOOH] = [                   ] M
  
  - [C₆H₄ClCOO⁻] = [                   ] M
  
  - [HCN] = [                   ] M
  
  - [CN⁻] = [                   ] M
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Transcribed Image Text:**Problem Statement: Acid-Base Equilibrium and pH Calculation** Calculate the pH of a solution prepared by dissolving 0.174 mol of *m*-chlorobenzoic acid (C₆H₄ClCOOH, Kₐ = 1.00×10⁻⁴) and 0.430 mol of hydrocyanic acid (HCN, Kₐ = 6.17×10⁻¹⁰) in water and diluting to 2.40 L. Also, calculate the equilibrium concentrations of C₆H₄ClCOOH, C₆H₄ClCOO⁻, HCN, and CN⁻. Do not make an approximation unless the initial acid concentration is greater than 1000 × Kₐ. (Hint: The pH will be determined by the stronger acid of this pair.) **Calculations Required:** - **pH**: [ ] - **Equilibrium Concentrations**: - [C₆H₄ClCOOH] = [ ] M - [C₆H₄ClCOO⁻] = [ ] M - [HCN] = [ ] M - [CN⁻] = [ ] M
Expert Solution
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Step 1

Given:

Moles of C6H4ClCOOH = 0.174 mol

Ka of C6H4ClCOOH = 1.00×10-4

Moles of HCN = 0.430 mol

Ka of HCN = 6.17 × 10-10

Volume = 3.00 L

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