
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:Calculate the pH of a solution containing 0.70 M HC2H3O2 and 0.25 M NaC2H302.
The K, for HC,H;0, is 1.8x10-5.
pH =
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- If 0.50 L 0.20 M HF solution is mixed with solution A to make a mixed solution with a total volume of 1.00 L. Kw = 1.00x10-14; Ka(HF) = 6.6x10-4 at T=298K. (a) If solution A is 0.50 L 0.20 M HNO3, calculate the pH of the mixed solution. Ka(HNO3) = 100 (b) If solution A is 0.50 L 0.20 M NH4CI, calculate the pH of the mixed solution. Ko(NH3) = 1.8×10-5 %3D (c) If solution A is 0.50 L 0.20 M HNO2, calculate the pH of the mixed solution. Ka(HNO2) = 5.1×104 Hint: First list an equation that shows electrical neutrality in the solution. Also, neglect the [H*] contribution from water. Then use [H*] and the equilibrium constant(s) to express the anion concentrations in the equation you obtained for electrical neutrality, and you will find there is single unknown [H*] in the equation.arrow_forwardThe ionization constant of acetic acid HC2H3O2 is 1.8 x 10-5. What will be the pH of a 0.10 M HC2H3O2 solution which is 0.10 M in NaC2H3O2arrow_forward8:43 1 ll 5GE Question 11 of 25 Submit The pH for 0.0715 M solution of CCl,CO2H is 1.40. Determine the value of Ka for CCl,CO2H. 1 2 Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. CCI,CO,H(+ H20(1) =H;0*(aq) +CCl,CO2 (ac Initial (M) Change (M) Equilibrium (M) 5 RESET 0.0715 1.40 -1.40 0.040 -0.040 0.032 -0.032 +x -X 0.0715 + x 0.0715 - 1.40 + x 1.40 - x 0.040 + x 0.0340 - x 0.032 + x 0.032 - xarrow_forward
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