calculate the pH after addition of 0.00, 5.00, 15.00, 25.00, 40.00, 45.00, 49.00, 50.00, 51.00, 55.00 and 60.00 ml of 0.1000M HCl in the titration of 50.00 ml of b) 0.1000 M ethylamine

Read sec. 14.7 2, then calculate the volume at equivalence and the pH at each of the following volumes of titrant for the titration of a 75.00 mL of a 0.049 mol L1 solution of nitrous acid (pKa = 3.37) titrated with 0.198 mol L' sodium hydroxide. %3D Ve = 18.6 mL VOH pH VOH 7.05 pH : VOH = = 12.1 pH %3D VOH = Ve %3D pH %3D Von = 27.8 pH = VoH = 55.7 pH Submit Question Jump to Answer

A chemist titrates 80.0 mL of a 0.3825 M ethylamine (C2H5NH2) solution with 0.8602 M HBr solution at 25 °C. Calculate the pH at equivalence. The pK, of ethylamine is 3.19. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ×

Be sure to answer all parts. Find the pH during the titration of 20.00 mL of 0.1000 M triethylamine, (CH3CH2)3N (K₁ = 5.2 × 10-4), with 0.1000 M HCl solution after the following additions of titrant. (a) 11.00 mL: pH = (b) 20.10 mL: pH= = (c) 29.00 mL: pH = X X X