Calculate the OH concentration and pH of a 3.6 x 10-³ M aqueous solution of sodium cyanide, NaCN, Finally, calculate the CN concentration. (K. (HCN) = 4.9 × 10-10) [OH-] = M pH = [CN] = M
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![Calculate the OH concentration and pH of a 3.6 x 10-³ M aqueous solution of sodium cyanide, NaCN.
Finally, calculate the CN concentration. (K. (HCN) = 4.9 × 10-10)
[OH-] =
M
pH =
[CN™]
=
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2d324e2-7a67-4e3d-bb22-9ad23fbeb72b%2F74b04365-b991-49e0-b1c5-22cdd62beec2%2Fzxfzihv_processed.jpeg&w=3840&q=75)
According to the question we have,
The concentration of the NaCN aqueous solution is given by (C) = 3.610-3 M
The equilibrium constant for the HCN is given by= Ka(HCN) = 4.910-10
We have to calculate the concentration of OH- and CN- and also the pH of the solution.
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