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Calculate the number density of valence electrons in a certain metallic element given that the element crystallises in a BCC structure with a lattice constant of 0.415 nm, and that the element is monovalent (i.e. each atom has a single valence electrons). Assuming that the mean free path of the electrons is 1.3 nm, calculate the collision time and the conductivity of the element at 350 K, using the classical Drude model of electrical conduction. O a. Electron density = 2.80 x 1028 m 3; collision time 1.03 x 10-14 s; conductivity = 8.13 x 106 'm1 O b. Electron density = 4.56 x 1028 m-3: collision time = 2.45 x 10-14 s; conductivity = 3.88 x 106 0Im-1 O c. Electron density = 6.53 x 1026 m-3: collision time = 2.45 x 10-14 s; conductivity = 9.26 x 105 'm1 d. Electron density 1.40 x 1028 m-3; collision time 1.03 x 10-14 s; conductivity = 4.07 x 106 Q 'm

Calculate the number density of valence electrons in a certain metallic element given that the element crystallises in a BCC structure with a lattice constant of 0.415 nm, and that the element is monovalent (i.e. each atom has a single valence electrons). Assuming that the mean free path of the electrons is 1.3 nm, calculate the collision time and the conductivity of the element at 350 K, using the classical Drude model of electrical conduction. O a. Electron density = 2.80 x 1028 m 3; collision time 1.03 x 10-14 s; conductivity = 8.13 x 106 'm1 O b. Electron density = 4.56 x 1028 m-3: collision time = 2.45 x 10-14 s; conductivity = 3.88 x 106 0Im-1 O c. Electron density = 6.53 x 1026 m-3: collision time = 2.45 x 10-14 s; conductivity = 9.26 x 105 'm1 d. Electron density 1.40 x 1028 m-3; collision time 1.03 x 10-14 s; conductivity = 4.07 x 106 Q 'm

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the number density of valence electrons in a certain metallic element given that the element crystallises in a BCC structure with a lattice constant of 0.415 nm, and that the element is monovalent (i.e. each atom has a single valence electrons). Assuming that the mean free path of the electrons is 1.3 nm, calculate the collision time and the conductivity of the element at 350 K, using the classical Drude model of electrical conduction. O a. Electron density = 2.80 x 1028 m-3, collision time = 1.03 x 10-14 s; conductivity = 8.13 x 106 0'm Electron density = 4.56 x 1028 m-3; collision time = 2.45 x 10-14 s; conductivity = 3.88 x 106 Qm- O c. Electron density = 6.53 x 1026 m 3; collision time 2.45 x 10-14 s; conductivity 9.26 x 105'm d. Electron density 1.40 x 1028 m-3; collision time 1.03 x 10-14 s; conductivity = 4.07 x 106 Q 'm
Transcribed Image Text:Calculate the number density of valence electrons in a certain metallic element given that the element crystallises in a BCC structure with a lattice constant of 0.415 nm, and that the element is monovalent (i.e. each atom has a single valence electrons). Assuming that the mean free path of the electrons is 1.3 nm, calculate the collision time and the conductivity of the element at 350 K, using the classical Drude model of electrical conduction. O a. Electron density = 2.80 x 1028 m-3, collision time = 1.03 x 10-14 s; conductivity = 8.13 x 106 0'm Electron density = 4.56 x 1028 m-3; collision time = 2.45 x 10-14 s; conductivity = 3.88 x 106 Qm- O c. Electron density = 6.53 x 1026 m 3; collision time 2.45 x 10-14 s; conductivity 9.26 x 105'm d. Electron density 1.40 x 1028 m-3; collision time 1.03 x 10-14 s; conductivity = 4.07 x 106 Q 'm
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