Calculate the moment of inertia of the shaded area about the x-axis. 79 mm 79 mm 52 mm
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Calculate the moment of inertia of the shaded area about the x-axis
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- Calculate the moment of inertia of the shaded area about the x-axis. 66 mm A 25 mm -*-. -41 mm 41 mm Answer: Ix= 100 (106) mm4: Consider the blue shaded triangle with a semicircular hole at the top. The figure is not to scale. y 123 тm 37 mm 74 mm a) Determine the moment of inertia around the a-axis of the triangle without the hole. I, mm (for the solid triangle). b) Determine the moment of inertia around the a- axis for the shaded region; i.e. the triangle with the hole. I, mm (for the triangle with the hole).Prob. 5. Calculate the moment of inertia of the shaded area about the x-axis. y = x²/3 1"
- Determine the moment of inertia of the shaded area about the x-axis. 5317.36 in4 3715.36 in4 5371.63 in4 5713.63 in4Determine the moment of inertia of the shaded area about the x-axis. y 18" 1 0" Answer: Ix= in.4The shaded area has the following properties:IX = 1.26 x 106 mm4= 6.55 x 105 mm4 andPxy. = −1.02 105 mm4 Determine the moments of inertia of the area about thex’ and v’ axes if θ=30
- Question 3 Determine the moment of inertia of the shaded area about the x and y axes. x² = 1² x- Ans:=bh³ 15Determine the moment of inertia in __ x 107 mm4 about the centroidal y-axis.03.20 5.90 0.90 1.60 radius circle ΜΟΜΕΝT OF INERTIA 0.90 5.00 radius circle 3.20 1. Locate the centroid of the 0.90 shaded figure. 2.50 radius circle 2. Compute the moment of inertia 5.00 of the shaded figure along the centroidal x-axis. 7.50 5.00 5.50
- Calculate the Moment of inertla in the beam shown In Figure by using the transformed area method, fc= 3000 psi, n= 9, and M= 70 ft-k. 17 in. 20 in. 3 #9 bars (A, 3.00 in.) 3 in. 10 in Select one: a. 4067 in b. 3837 in c. 3990 in d. 4125 in| 10 pts. 1. Determine the centroidal x-axis from the x-axis and the moment of inertia about centroidal x-axis for the shaded area in the figure below. 5m 3m 3m 5m 2m 1.5m 2m 3m 8mDetermine the magnitudes of the velocities of points A and B. 16 mm- 60 mm B Anwers: VA = m/s VB = i m/s