Calculate the molarity of a solution prepared by dissolving 110.0 mg of KMNO4 (158 g/mol) in enough water to make 150.0 mLsolution. The solution will be used to oxidize FeCl2 according to the following reaction (unbalanced):KMNO4 + FeCl2+ HCI → MnO2+ FeCl3 + H2O + KCIO 4.64x 10-3 MO 2.32 x 10-2 MO 4.46 x 103MO 9.28 x 10-3 M

Given that the weight of KMnO4(W) = 110.0 mg = 110.0 x 10-3 grams volume if the solution(V) = 150.0…

Answered: Calculate the molarity of a sol…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The discharge of chromate ions (CrO42) to sewers or natural waters is of concern because of both its ecological impacts and effects on human health if the receiving water is used as a drinking water source. One way in which chromate can be removed from solution is by its reaction with ferrous iron (Fe²+) to form a mixture of chromic hydroxide and ferric hydroxide solids [Cr(OH)3(s) and Fe(OH)3(s), respectively], which can then be filtered out of the water. The overall reaction can be represented as CrO4 + 3Fe²+ + 8H₂O → Cr(OH)3(s) + Fe(OH)3(s) + 4H+ How much particulate matter would be generated daily by this process at a facility that treats 60 m³/h of a waste stream containing 40 µg/L CrO4²- if the treatment reduced the Cr concentration enough to meet a discharge limit of 10 µg/L (MCL proposed in 2013, voted into law in 2015 and ruled invalid in 2017 for California) or 50 µg/L (current MCL) CrO4²-?
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Be sure to answer all parts.Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following reactions. Include phase abbreviations in the overall, balanced molecular equation. Enter only the elemental symbol when identifying which element is oxidized or reduced. (a) Mg(s) + Cr(C2H3O2)3(aq) oxidized: reduced:
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