Calculate the mass, in grams, of potassium iodide that must be added to a 125-mL volumetric flask in order to prepare 125 mL of a 0.143 M aqueous solution of the salt. grams

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Problem Statement:**

Calculate the mass, in grams, of **potassium iodide** that must be added to a **125-mL** volumetric flask in order to prepare **125 mL** of a **0.143 M** aqueous solution of the salt.

**Input Box:**

[_____] grams

---

**Explanation:**

This question aims to apply concepts from chemistry, specifically molarity and solution preparation. You are tasked to determine the mass of potassium iodide (KI) needed to create a specific molar concentration in a given volume of solution. 

**Key Points:**

- **Molarity (M)** is defined as the number of moles of solute per liter of solution.
- The volume needed is 125 mL, which is equivalent to 0.125 L.
- The desired molarity of the potassium iodide solution is 0.143 M.

**Steps for Solution:**

1. Use the formula for molarity:
   \[
   \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}}
   \]
2. Calculate the number of moles of potassium iodide required:
   \[
   \text{moles of KI} = \text{Molarity} \times \text{Volume in liters}
   \]
3. Convert moles to grams using the molar mass of potassium iodide (approximately 166 g/mol).

**Note:**
This exercise reinforces calculation skills in chemistry, specifically focusing on solution preparation and understanding molarity.
Transcribed Image Text:**Problem Statement:** Calculate the mass, in grams, of **potassium iodide** that must be added to a **125-mL** volumetric flask in order to prepare **125 mL** of a **0.143 M** aqueous solution of the salt. **Input Box:** [_____] grams --- **Explanation:** This question aims to apply concepts from chemistry, specifically molarity and solution preparation. You are tasked to determine the mass of potassium iodide (KI) needed to create a specific molar concentration in a given volume of solution. **Key Points:** - **Molarity (M)** is defined as the number of moles of solute per liter of solution. - The volume needed is 125 mL, which is equivalent to 0.125 L. - The desired molarity of the potassium iodide solution is 0.143 M. **Steps for Solution:** 1. Use the formula for molarity: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \] 2. Calculate the number of moles of potassium iodide required: \[ \text{moles of KI} = \text{Molarity} \times \text{Volume in liters} \] 3. Convert moles to grams using the molar mass of potassium iodide (approximately 166 g/mol). **Note:** This exercise reinforces calculation skills in chemistry, specifically focusing on solution preparation and understanding molarity.
In the laboratory, a student adds 14.2 g of copper(II) iodide to a 500. mL volumetric flask and adds water to the mark on the neck of the flask. Calculate the concentration (in mol/L) of copper(II) iodide, the copper(II) ion, and the iodide ion in the solution.

\[[\text{CuI}_2] = \_\_\_\_\ M\]

\[[\text{Cu}^{2+}] = \_\_\_\_\ M\]

\[[\text{I}^-] = \_\_\_\_\ M\]
Transcribed Image Text:In the laboratory, a student adds 14.2 g of copper(II) iodide to a 500. mL volumetric flask and adds water to the mark on the neck of the flask. Calculate the concentration (in mol/L) of copper(II) iodide, the copper(II) ion, and the iodide ion in the solution. \[[\text{CuI}_2] = \_\_\_\_\ M\] \[[\text{Cu}^{2+}] = \_\_\_\_\ M\] \[[\text{I}^-] = \_\_\_\_\ M\]
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